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3 years ago

Salt water is classified as a

2 answers:

7 0

Salt Water is classified as a:

4) mixture because the proportion of its components can vary.

Salt water is composed of salt and water. Regardless of the amount of salt or water put together, these two still form salt water.

LekaFEV [45]3 years ago

4 0

Answer:

4) mixture

Explanation:

The answer is 4) because salt water has 2 properties which are salt and water. Never the less the amount of salt or water you keep adding the substance would always remain as salt water.

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Do you agree or disagree with the statement: "A rise of -7°C" means "a fall of 7°C"? Explain.

vazorg [7]

Answer:

i would agree

Explanation:

5 0

2 years ago

All answers must have the correct unit! (g/mL) d= mass/volume, d= masa/volumen

Radda [10]

heh.......... sorry man............... but this was posted over 5 hours ago........ so nobody is gonna see it and you probably dont need the answer anymore..... so errrr..... imma justtttt..... take these points :D

8 0

3 years ago

According to the equation, 2 H2 + O2 --> 2 H20, how many moles of oxygen are required to convert 12 moles of hydrogen to wate

DerKrebs [107]

Answer:

6 moles of oxygen, or 3O2.

Explanation:

I would build a proportion for this:

$\frac{2(2)}{2} = \frac{12}{x} \\ 4x = 24 \\ x = 6$

5 0

3 years ago

The airbags that protect people in car crashes are inflated by the extremely rapid decomposition of sodium azide, which produces

Oxana [17]

Answer:

1. NaN₃(s) → Na(s) + 1.5 N₂(g)

2. 79.3g

Explanation:

<em>1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN₃) into solid sodium and gaseous dinitrogen.</em>

NaN₃(s) → Na(s) + 1.5 N₂(g)

<em>2. Suppose 43.0L of dinitrogen gas are produced by this reaction, at a temperature of 13.0°C and pressure of exactly 1atm. Calculate the mass of sodium azide that must have reacted. Round your answer to 3 significant digits.</em>

First, we have to calculate the moles of N₂ from the ideal gas equation.

$P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{1atm.(43.0L)}{(0.08206atm.L/mol.K).286.2K} =1.83mol$

The moles of NaN₃ are:

$1.83molN_{2}.\frac{1molNaN_{3}}{1.5molN_{2}} =1.22molNaN_{3}$

The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:

$1.22mol.\frac{65.01g}{mol} =79.3g$

5 0

3 years ago

A latex balloon at sea level and room temperature (25°C) has a volume of 2.42 L. When the balloon is released by the child holdi

yarga [219]

Answer:

The answer to your question is: V2 = 1.94 l

Explanation:

Data

V1 = 2.42 l

T1 = 25°C

P1 = 1 atm

V2 = ?

T2 = 25 -11 = 14°C

P2 = 1(0.7) = 0.7 atm

Formula

P1V1/T1 = P2V2/T2

Clear V2 from the equation

V2 = P1V1T2/ P2T1

V2 = (1)((2.42)(14) / (0.7)(25)

V2 = 33.88 / 17.5

V2 = 1.94 l

6 0

3 years ago