Answer:
A. [isocitrate]/[citrate] = 0.724
B. [citrate] = 24.1 mM
Explanation:
Using the equation, ∆G'° = -RTlnK'eq
Where, ∆G'° = 0.8 KJ/mol = 800 J/mol; R is molar gas constant = 8.315 J/mol; T is standard temperature = 298 K; Keq is equilibrium constant = [isocitrate]/[citrate]
Making Keq subject of formula in the above equation;
Keq = e^(-∆G'°/RT)
= e^ {-800/(8.315*298)}
= e^(-0.323)
Keq = 0.724
Therefore, [isocitrate]/[citrate] = 0.
724
B. Keq = [isocitrate]/[citrate]
Where Keq = 0.724, [isocitrate] = 0.03mM.
[citrate] = Keq/[isocitrate]
= 0.724/0.03
[citrate] = 24.1 mM
Given that CaCl2 = 2.46 m
Therefore 2.46 mole of CaCl2 present in 1.00 g of solution
Mass of 2.46 mole CaCl2= number of mole * molar mass
= 2.46 mole * 110.98 g/mol
= 273.01 g
Mass of water or solvent = mass of solution – mass of solute
= 1000 g -273.01 g
= 726.99 g
Mole of water = amount in g / molar mass
= 726.99 g/18.02 g/ mole
= 40.34 moles
Mole fraction of CaCl2 = number of mole of CaCl2 / total moles
= 2.46 /2.46+40.34
= 2.46/42.8
= 0.057
Answer:
C. 0.04 moles per cubic decimeter.
Explanation:
The molar mass of the Iodine is 253.809 grams per mole and a cubic decimeter equals 1000 cubic centimeters. The concentration of Iodine (), measured in moles per cubic decimeter, can be determined by the following formula:
(1)
Where:
- Mass of iodine, measured in grams.
- Molar mass of iodine, measured in grams per mol.
- Volume of solution, measured in cubic decimeters.
If we know that , and , then the concentration of iodine in a solution is:
Hence, the correct answer is C.
Answer:
The equilibrium concentration of chlorine gas, Cl₂(g), is 0.0625 M
Explanation:
Chemical equilibrium is established when there are two opposite reactions that take place simultaneously at the same speed, so that no changes are observed as time passes, despite the fact that the substances present continue to react with each other.
The mathematical expression that represents Chemical Equilibrium is known as the Law of Mass Action and is stated as: The ratio of the product of high concentrations to the stoichiometric coefficients in the reaction of products and reactants remains constant at equilibrium. For any reaction:
aA + bB ⇄ cC + dD
the equilibrium constant Kc is calculated as:
In this case, you have:
2 ICl(g) → Cl₂(g) + I₂(g)
So, the equilibrium constant Kc is:
Being:
- Kc= 0.10
- [Cl₂]= ?
- [ICl]= 0.50 M
- [I₂]= 0.40 M
Replacing:
Solving:
0.1= 1.6 * [Cl₂]
[Cl₂]= 0.1 ÷ 1.6
[Cl₂]= 0.0625 M
<u><em>The equilibrium concentration of chlorine gas, Cl₂(g), is 0.0625 M</em></u>
Metals usually melt when forming iron