All categories

3 years ago

The formula V1/T1 = V2/T2 applies to _____.

Chemistry

2 answers:

Furkat [3]3 years ago

8 0

Charles' law would be your answer

Flauer [41]3 years ago

3 0

Your answer will Be D.

You might be interested in

Suppose oxygen was much less electronegative than it is, so that hydrogen-oxygen bonds were much less polar and hydrogen bonds c

spayn [35]

Water would have a much lower boiling point much like its other hydrides and it would loss its ability to dissolve polar substances plus it couldn't form water columns so no more cohesion between water molecules

6 0

3 years ago

Read 2 more answers

Which of the following solutions would show the greatest conductivity at 30°C?

Nataly_w [17]

Your answer will be A

7 0

3 years ago

WHOEVER CAN HELP MEEEEE SAY "I" AND I WILL GIV U MANY MANY POINTS, THANKS, BRAINLIEST!!!! PLSSSSSSSSS

Gwar [14]

1: Biosphere

2: Atmosphere

3: Hydrosphere

4: Atmosphere (I think?)

5: Stratosphere

6: Biosphere

7: Hydrosphere

8: Geosphere

4 0

2 years ago

How many moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 ATM

Rama09 [41]

Answer:

285.4 moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 atm.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

P= 200.8 atm
V= 35 L
n=?
R= 0.082 $\frac{atm*L}{mol* K}$
T= 27.3 C= 300.3 K (being O C= 273 K)

Replacing:

200.8 atm* 35 L= n* 0.082 $\frac{atm*L}{mol* K}$ * 300.3 K

Solving:

$n=\frac{200.8 atm* 35 L}{0.082\frac{atm*L}{mol* K} * 300.3 K}$

n= 285.4 moles

285.4 moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 atm.

5 0

3 years ago

A solution is prepared by dissolving 4.40 g of KSCN in enough water to make 200 mL of solution. What is the concentration of the

attashe74 [19]

First find the number of moles of KSCN is in 4.40g of KSCN 1. Number of moles = mass given (4.40g) / molecular weight(MW) (KSCN) - to calculate MW, look for each element in the periodic table and add their atomic weight 2. Convert 200mL to liters 3. Concentration = number of moles/ volume in liters from (#2)

4 0

3 years ago

Read 2 more answers