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abruzzese [7]
3 years ago
7

what advantage might there be to having the encoder located on the motor side of the gearhead instead of at the output shaft of

the gearhead
Engineering
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

The definition is defined in the clarification segment following the table, as per the particular circumstance.

Explanation:

  • In something like a closed-loop device, shaft encoders were being used, the output of which could be influenced either by encoder location. Most motors have been used for gearbox speed reduction (RPM). Assume there's also a gearbox reduction of 30:1 as well as the motor is already spinning at a higher 3000 rpm, then the outcome feature shaft speed would be 100 rpm.
  • This suggests that every other output shaft turning correlates to 30 input shaft flips, and even if the encoder contains 40 holes through its diameter, instead every output shaft revolution contributes to 40\times 30=1200 pulses. That implies an accuracy of 0.3 degrees of rotation of the final output shaft (\frac{360 \ degree}{1200} =0.3).  

Accuracy as well as reliability are thus given by positioning the encoder on the engine side instead of on the outcome shaft including its gear head.

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A 750-turn solenoid, 24 cm long, has a diameter of 2.3 cm . A 19-turn coil is wound tightly around the center of the solenoid. P
oksian1 [2.3K]

Answer: 2.26x10^-4 v

Explanation:

Lenght of the selonoid = 24x10^-2m

Diameter of the selonoid = 2.3cm

The radius will then be = 1.15cm = 1.15x10^-2m

The area of the selonoid = ¶r^2 = 3.142 x (1.15x10^-2)^2 = 0.000415m^2.

Number of turns on selonoid N1 is 750

For the small center coil, number of turns N2 is 19.

There is a change in current dI/dt from 0 to 5.1 in 0.7s, dI/dt = (5.1-0)/0.7

dI/dt = 7.29A/s.

Induced EMF on selonoid due to magnetic Flux due to changing current in small coil is given as;

E = -M(dI/dt), where M is the mutual inductance of the coils.

but M = (u°AN1N2)/L, where u°= 4¶x10^-7,

A = area of selonoid,

L = Lenght of selonoid.

M = (4¶X10^-7X0.000415X750X19)/(24X10^-2)

M = 3.096X10^-5H

Induced EMF E = 3.096X10^-5 x 7.29

E = 2.26x10^-4V

6 0
4 years ago
Https://screenshot.best/2QA8H0<br><br><br><br><br><br> Check screen shot
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Answer:

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Explanation:

5 0
3 years ago
A system consists of a disk rotating on a frictionless axle
kakasveta [241]

The system includes a disk rotating on a frictionless axle and a bit of clay transferring towards it, as proven withinside the determine above.

<h3>What is the angular momentum?</h3>

The angular momentum of the device earlier than and after the clay sticks can be the same.

Conservation of angular momentum the precept of conservation of angular momentum states that the whole angular momentum is usually conserved.

  1. Li = Lf where;
  2. li is the preliminary second of inertia
  3. If is the very last second of inertia
  4. wi is the preliminary angular velocity
  5. wf is the very last angular velocity
  6. Li is the preliminary angular momentum
  7. Lf is the very last angular momentum

Thus, the angular momentum of the device earlier than and after the clay sticks can be the same.

Read more about the frictionless :

brainly.com/question/13539944

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