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marshall27 [118]
3 years ago
10

Which is an advantage of AC over DC power?

Physics
2 answers:
CaHeK987 [17]3 years ago
6 0

Answer:

The correct choice is

A. AC voltage can be transformed into other voltages through transformers.

Explanation:

We can convert an AC Voltage to other higher or lower voltage making use of a step up or step down transformer. Electricity is transferred over long distances at high voltages as the losses are minimum at high voltage. The electricity can not be used in households at such high voltage. So the high voltage is converted to low voltage using transformers. This can only be done in case of AC Power.

Zanzabum3 years ago
4 0
Its A......................................................................................
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Which test was conducted on the skin found under the victim’s nails?
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Y-STR analysis. It is a DNA test used to compute and match with the possibility via lap.
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You see lightning and 30 seconds later you hear thunder. how far away is the thunderstorm? take the speed of sound to be 339 m/s
Jobisdone [24]
Let the observer be 'd' distance away from the thunderstorm and let light take 't' time to reach the observer
Since the speed of sound and light remains constant in a particular medium, we can use
      Speed = Distance/Time

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   3 x 10^8 = d/t
                t = d/(3 x 10^8)   -1 

For sound,
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tatuchka [14]
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5 0
2 years ago
Two parallel wires carry currents in the same direction. If the currents in the wires are 1A and 4A and the wires are 5 m apart.
serious [3.7K]

Answer:

1.6\times 10^{-7} N

2.4\times 10^{-7} N

Explanation:

i_{1} = 1 A

i_{2} = 4 A

r = distance between the two wire = 5 m

F = Force per unit length acting between the two wires

Force per unit length acting between the two wires is given as

F = \frac{\mu _{o}}{4\pi }\frac{2i_{1}i_{2}}{r}

F = (10^{-7})\frac{2(1)(4)}{5}

F = 1.6\times 10^{-7} N

r'} = distance of each wire from the midpoint = 2.5 m

Magnetic field midway between the two wires is given as

B = \frac{\mu _{o}}{4\pi } \left \left ( \frac{2i_{2}}{r'} \right - \frac{2i_{1}}{r'} \right \right ))

B = (10^{-7}) \left \left ( \frac{2(4)}{2.5} \right - \frac{2(1)}{2.5} \right \right ))

B = 2.4\times 10^{-7}

5 0
2 years ago
A mxiture of n2 and H2 has mole fraction of 0.4 and 0.6 respectively. Determine the density of the mixture at one bar and 0 c.
SOVA2 [1]

Answer:

The density of the mixture is 0.55kg/m^3

Explanation:

P = 1bar = 100kN/m^2, T = 0°C = 273K, n = 0.4+0.6 = 1mole

PV = nRT

V = nRT/P = 1×8.314×273/100 = 22.70m^3

Mass of N2 = 0.4×28 = 11.2kg

Mass of H2 = 0.6×2 = 1.2kg

Mass of mixture = 11.2 + 1.2 = 12.4kg

Density of mixture = mass/volume = 12.4/22.7 = 0.55kg/m^3

3 0
3 years ago
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