The relative velocity of the athlete relative to the ground is 5.2 m/s
The given parameters;
constant velocity of the athlete, V = 5.2 m/s
let the velocity of the ground = Vg = 0
The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.
The athlete is the moving object in this question while the ground is stationary.
The relative velocity of the athlete relative to the ground is calculated as follows;

Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s
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Answer:
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Answer:
Explanation:
given,
ω₁ = 120 rpm
1 rpm = 
rad/s
= 12.56 rad/s
α = - 4 rad/s²
diameter of disk = 20 cm
final angular velocity = 0
t = 
t = 
t = 3.14 s.
2) 
= 
= 19. 72 radians
3) total angular distance rotated
x = θ R
x = 19.72 × 0.1 = 1.97 m
x = 2 m