A particle confined to move along a curved path has only one degree of freedom. inclined plane are some examples of constrained motion. Every condition of constraint reduces the number of degree of freedom by one.
I hope this helps!
Answer:
Period, T = 10.86 seconds
Frequency, f = 0.092 Hz
Wavelength,
Speed, v = 3.61 m/s
Explanation:
It is given that,
A woman notices that a wave crest passes by, five more crests pass in a time of 54.0
.
The distance between two successive crests is, the wavelength of wave,
(b)Frequency of a wave is given by number of oscillations per second such that,
f = 0.092 Hz
(a) Let T is the period of the wave. It is inverse of frequency of a wave such that,
T = 10.86 seconds
(c) The distance between two successive crest or trough is called wavelength of a wave, .
(d) The speed of a wave is given by :
v = 3.61 m/s
Hence, this is the required solution.
This molecule is formed between a not very electronegative metal and a very electronegative nonmetal which means it should be an ionic compound which would mean that it would have the name of potassium oxide.
look up the naming rules for ionic compounds. I would explain it here but I don't know how to explain naming the anion part of the molecule other than it ends in ide since it is a monoatomic anion which is why oxide is in the name instead of oxygen.
I hope this helps. Let me know if anything is unclear or needs more explanation.
Answer:
<h2>The work done is 0.882 Joules.</h2>
Explanation:
To calculate the work, we need to find all forces that are involved in the movement.
As you can analyse, the body is the force that make the box to move, and the friction force is opposite to it, we cannot forget about the friction. So, we have to calculate the resultant force to this context.
So, to find we use: ; where
The friction force would be:
Then, the resultant force is:
Now, we calculate the work:
Therefore, the work done is 0.882 Joules.
Volume % = mole %
Molar mass of oxygen = 32kg/kmol
Molar mass of nitrogen = 28 kg/kmol
Density of nitrogen = Density of
oxygen x molar mass of oxygen x molar ratio of air x molar mass of nitrogen
Density of nitrogen = (1.43kgm^-3)(1 kmol O2/32 kg O2)(80 kmol N2/ 20
kmol O2)(28 kg N2/1 kmol O2) = 5.01 kg/m3