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Greeley [361]
3 years ago
12

I don’t get my physical science hw it’s about ocean currents

Physics
1 answer:
OLEGan [10]3 years ago
8 0
Okay I’ll help you with some

11. Anchorage has the coldest average temperature because its the furthest north

7. The temperatures lower in Albuquerque because it has a higher elevation

10. Miami has the highest average temperature because it’s the closet to the equator

9. San Diego has warmer winter temperatures than Albuquerque because the elevation is lower in San Diego
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An enemy spaceship is moving toward your starfighter with a speed, as measured in your frame, of 0.400c. The enemy ship fires a
kvasek [131]

Answer:

0.859375c

31.03 seconds

Explanation:

v' = Velocity of my ship = 0.4 c

u = Velocity of rocket = 0.7 c

c = Speed of light = 3\times 10^8\ m/s

s = Distance between my ship and enemy ship = 8\times 10^6\ km

Relativistic addition of speed is given by

v=\dfrac{v'+u}{1+\dfrac{uv'}{c^2}}\\\Rightarrow v=\dfrac{0.7+0.4}{1+\dfrac{0.7c\times 0.4c}{c^2}}\\\Rightarrow v=0.859375\ c

The speed of the missile is 0.859375c

Time is given by

t=\dfrac{s}{v}\\\Rightarrow t=\dfrac{8\times 10^9}{0.859375\times 3\times 10^8}\\\Rightarrow t=31.03\ s

It will take 31.03 seconds to reach me.

6 0
3 years ago
Please help me in science plss​ <br><br><br>I give brainliest to Answer this plss
Elenna [48]
Stan looga
this is correct answer
8 0
3 years ago
A car moves at a constant velocity of 30 m/s and has 3.6 × 105 J of kinetic energy. The driver applies the brakes and the car st
LekaFEV [45]

The force needed to the stop the car is -3.79 N.

Explanation:

The force required to stop the car should have equal magnitude as the force required to move the car but in opposite direction. This is in accordance with the Newton's third law of motion. Since, in the present problem, we know the kinetic energy and velocity of the moving car, we can determine the mass of the car from these two parameters.

So, here v = 30 m/s and k.E. = 3.6 × 10⁵ J, then mass will be

K.E = \frac{1}{2} * m*v^{2}  \\\\m = \frac{2*KE}{v^{2} } = \frac{2*3.6*10^{5} }{30*30}=800 kg

Now, we know that the work done by the brake to stop the car will be equal to the product of force to stop the car with the distance travelled by the car on applying the brake.Here it is said that the car travels 95 m after the brake has been applied. So with the help of work energy theorem,

Work done = Final kinetic energy - Initial kinetic energy

Work done = Force × Displacement

So, Force × Displacement = Final kinetic energy - Initial Kinetic energy.

Force * 95 = 0-3.6*10^{5}\\ \\Force =\frac{-3.6*10^{5} }{95}=-3.79 N

Thus, the force needed to the stop the car is -3.79 N.

5 0
3 years ago
The distance covered by a car at a time, t is given by x = 20t + 6t4, calculate
Anni [7]

Answer:

(i) v = 44 m/s

(ii) a = 72 m/s^2

Explanation:

You have the following equation for the potion of a car:

x=20t+6t^4

(i) The instantaneous velocity is the derivative of x in time:

\frac{dx}{dt}=20+(6)(4)t^3=20+24t^3

for t = 1 is:

v(t=1)=\frac{dx}{dt}=20+24(1)^3=44m/s

(ii) The instantaneous acceleration is the derivative of the velocity:

\frac{dv}{dt}=24(3)t^2=72t^2

for t = 1

a(t=1)=\frac{dv}{dt}=72(1)^2=72m/s^2

8 0
4 years ago
Convert 200in/10s into m/s (1m = 39.37in)
stiv31 [10]
5.08




hope you got it right !
7 0
4 years ago
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