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marishachu [46]
3 years ago
5

A toy boat moves horizontally in a pond. The horizontal position of the boat in meters over time is shown below. What is the dis

placement of the boat between 0s and 16s? What is the distance traveled by the boat between 0s and 16s?
Physics
1 answer:
arsen [322]3 years ago
5 0

Answer:

displacement=-21

distance=39

Explanation:

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A 15,000 kg rocket traveling at +230 m/s turns on its engines. Over a 6.0 s period it burns 1,000 kg of fuel. An observer on the
lesya692 [45]

Answer:

a) v = 312.791\,\frac{m}{s}, b) a = 13.333\,\frac{m}{s^{2}}

Explanation:

The problem is asking the rocket velocity and acceleration at t = 6 s.

a) The general equation of the rocket is:

v=v_{o} -v_{ex}\cdot \ln \frac{m}{m_{o}}

v = 230\,\frac{m}{s}-(1200\,\frac{m}{s} )\cdot \ln \frac{14000\,kg}{15000\,kg}

v = 312.791\,\frac{m}{s}

b) The acceleration experimented by the rocket is:

a = \frac{v_{ex}}{m_{o}}\cdot \frac{dm}{dt}

a = \frac{1200\,\frac{m}{s} }{15000\,kg}\cdot \frac{1000\,kg}{6\,s}

a = 13.333\,\frac{m}{s^{2}}

3 0
4 years ago
Read 2 more answers
A car leaves a garage at 10 mph. it speeds up to 20 miles per hour in the city and eventually increases to 50 miles per hour in
LekaFEV [45]

Average speed = (total distance covered) / (time to cover the distance)

= (50 miles) / (1.5 hours)

= (50/1.5) miles/hours

= (33 and 1/3) mph .

We don't care about all that other "data" given earlier in the question.
We only need to know the total distance covered and the time it took
to cover the distance.
4 0
3 years ago
On a rectangle with length 100 m, width 50m and 2 vehicles stationed together. Find the time that they meet given that car A tra
zhannawk [14.2K]

Answer:

T=35.625sec

Explanation:

From the question we are told that:

Length L=100 m

Width W=50m

Velocity of Car A V_A=5m/s

Velocity of Car B V_B=3m/s

Distance traveled by car A before car B moves

d_l=5*3

d_l=15

Therefore total distance traveled at same time interval

D=total\ distance-d_l

Where

Total distance=Perimeter of rectangle

P=2(L+B)

P=2(100+50)

P=300

Therefore

D=total\ distance-d_l

D=300-15\\D=285m

Generally the equation for time taken to meet is mathematically given by

T=\frac{Distance D}{Relative\ speed V_r}

Where

Relative speed = Speed of car A +Speed of car B

V_r=V_A+V_B

V_r=5+3

V_r=8m/s

Therefore the time taken to meet

T=\frac{ D}{ V_r}

T=\frac{ 285}{ 8}

T=35.625sec

8 0
3 years ago
A car travels 150 meters East of its original starting position in 15s. What is the cars velocity?​
Andrew [12]

Answer:

it is 347

Explanation:

6 0
3 years ago
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Suppose a piece of food is on the edge of a rotating microwave oven plate. Does it experience nonzero tangential acceleration, c
Rus_ich [418]

Answer:

Explanation:

(a) When the plate starts to spin:

Its angular velocity increases, so the angular acceleration is non zero. As the direction of velocity keeps on changing every instant so the linear acceleration is also non zero.

(b) When the plate rotates at constant angular velocity:

Its angular velocity is constant so the angular acceleration is zero. As the direction of velocity keeps on changing every instant so the linear acceleration is also non zero.

(c) When the plate sows to halt:

Its angular velocity decreases, so the angular acceleration is non zero( but negative). As the direction of velocity keeps on changing every instant so the linear acceleration is also non zero.

4 0
3 years ago
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