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iogann1982 [59]
3 years ago
9

A 160 g air-track glider is attached to a spring. The glider is pushed in 11.2 cm and released. A student with a stopwatch finds

that 14.0 oscillations take 19.0 s . You may want to review (Pages 400 - 402) . For help with math skills, you may want to review: Solving Radical Equations For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Mass on a spring. Part A What is the spring constant
Physics
1 answer:
Yanka [14]3 years ago
6 0

Answer:

k = 3.41 N/m

Explanation:

The time period is given as:

T = \frac{time\ taken}{No.\ of\ oscillations} \\\\T = \frac{19\ s}{14} \\\\T = 1.36\ s

Another formula for the time period of the spring-mass system is:

T = 2\pi\sqrt{\frac{m}{k}} \\\\(1.36\ s)^2 = 4\pi^2\frac{0.16\ kg}{k}\\\\k = \frac{(4\pi^2)(0.16\ kg)}{(1.36\ s)^2}\\\\

<u>k = 3.41 N/m</u>

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Waning Gibbous would be the phase?
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With what force will a car hit a tree if the car has a mass of 3,550 kg and it is accelerating at a rate of 2.5 m/s2 on a snowy
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Answer:

<h2>8875 N</h2>

Explanation:

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Snowboarder Jump—Energy and Momentum
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Answer:

THE ANSWER TERMS ARE DEFINED BLOW:-

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4 0
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You find an unmarked blue laser on your way to physics class. When you get to class you realize you can determine the wavelength
Afina-wow [57]

Answer:

λ = 451.7 nm

Explanation:

The expression for the constructive interference of the double diffraction experiment is

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let's use trigonometry

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how the experiment occurs at very small angles

          tan θ = sin θ / cos θ = sin θ

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we substitute

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let's calculate

          λ = \frac{0.342 \ 10^{-3} \ 2.80 \ 10^{-3} }{1 \ 2.12 }

          λ = 4.51699 10⁻⁷ m

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4 0
3 years ago
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