Answer:
True
Explanation:
It can cause flooding and destruction of habitat because of dammed rivers create large reservoirs upstream which can spill out to the surrounding during heavy rainfall causing flooding and destruction of natural habitat.
Answer:
i would like to help you but I can't help you i don't understand the question and i don't speak Spanish
Given Information:
Current = I = 2.5 A
Magnetic field = B = 0.10 T
Radius = r = d/2 = 0.02/2 = 0.01 m
Length = L = 8 cm = 0.08 m
Required Information:
Number of turns = N = ?
Answer:
Number of turns = N ≈ 2547 turns
Step-by-step explanation:
The approximate model to find the number of turns is given by
B = μ₀nI
Where n = N/L
so
B = μ₀NI/L
N = BL/μ₀I
Where B is the magnetic field, L is the length of the solenoid, I is the current and μ₀ is the permeability of free space
N = (0.10*0.08)/(4πx10⁻⁷*2.5)
N ≈ 2547 Turns
The magnetic part using the Lorentz force is: F = q v x
B,
where v and B are vectors and v x B is the vector cross product.
Magnitude of the force: F = q v B sin(α)
So, sin(α) = F/( e v B), with e the proton charge.
This will give you a value for sin(α), and two potentials
for its opposite.
You will now look for:
sin(α) = 7.40 10^-13/( 1.60 10^-19 * 5 10^6 * 1.78)
= 0.520
So either sin(α) = 0.502 or sin(α) = -0.502
The 1st α = 30.1 degrees or α = 150 degrees.
The 2nd α = 210 degrees or α = 330 degrees.
So we can say that 30.1 degrees and 330 degrees would be minimum and biggest on [0,360]
Answer:
(a) the tangential speed of a point at the edge is 3.14 m/s
(b) At a point halfway to the center of the disc, tangential speed is 1.571 m/s
Explanation:
Given;
angular speed of the disc, ω = 500 rev/min
diameter of the disc, 120 mm
radius of the disc, r = 60 mm = 0.06 m
(a) the tangential speed of a point at the edge is calculated as follows;
Tangential speed, v = ωr
v = 52.37 rad/s x 0.06 m
v = 3.14 m/s
(b) at the edge of the disc, the distance of the point = radius of the disc
at half-way to the center, the distance of the point = half the radius.
r₁ = ¹/₂r = 0.5 x 0.06 m = 0.03 m
The tangential velocity, v = ωr₁
v = 52.37 rad/s x 0.03 m
v = 1.571 m/s
