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Pie
3 years ago
11

What happens to the temperatures when we have direct sunlight vs indirect sunlight?

Chemistry
1 answer:
lawyer [7]3 years ago
7 0

Explanation:

When we have direct sunlight, the temperature is higher compared to indirect sunlight.

Direct sunlight is usually overhead whereas indirect sunlight is at an angle to the surface.

  • Direct sunlight impacts the surface with more energy concentrated on a smaller surface area.
  • This warms the surface more.
  • Indirect sunlight is diffuse and spreads over a wider area.
  • This leads to a reduction in temperature.
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What is a number at the bottom right of an element in a chemical equation called?
Ann [662]

Answer:

There’s a particular way of writing what’s in a molecule called a chemical formula. The chemical formulae for all the elements that form each molecule and uses a small number to the bottom right of an element’s symbol to stand for the number of atoms of that element. For example, the chemical formula for water is H 2 O.

Explanation:

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3 years ago
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Complete and balance the equation for the reaction of sodium with water.<br> Na+_H2O+ H2
valentina_108 [34]

2Na + 2H2O → 2NaOH + H2

The balanced equation

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2 years ago
which of the following compounds would be considered an electrolyte? a. c6h12o6 b. naoh c. co2 d. agcl
AlekseyPX

Answer: B: NaOH

Explanation:

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8 months ago
Simplify the numercial expression 13-2x5
Tema [17]

Answer:

3

Explanation:

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4 0
3 years ago
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Using the volumes of sodium thiosulfate solution you just entered, the mass of bleach sample, and the average molarity of the so
dedylja [7]

Answer:

3.18 (w/w) %

Explanation:

In the problem, you can find mass of NaClO knowing the reaction of NaClO with Na₂S₂O₃ is:

NaClO + 2Na₂S₂O₃ + H₂O → NaCl + Na₂S₄O₆ +2NaOH + NaCl

<em>Where 1 mole of NaClO reacts with 2 moles of Na₂S₂O₃</em>

<em> </em>Moles of thiosulfate in the titration are:

0.0101L ₓ (0.042mol / L) = 4.242x10⁻⁴ moles of Na₂S₂O₃

Thus, moles of NaClO in the initial solution are:

4.242x10⁻⁴ moles of Na₂S₂O₃ ₓ (1mol NaClO / 2 mol Na₂S₂O₃) = 2.121x10⁻⁴ moles NaClO

As molar mass of NaClO is 74.44g/mol, mass of 2.121x10⁻⁴ moles are:

2.121x10⁻⁴ moles ₓ (74.44g / mol) = <em>0.0158g of NaClO</em>

As mass of bleach is 0.496g, mass percent is:

0.0158g NaClO / 0.496g bleach ₓ 100 =

<h3>3.18 (w/w) % </h3>
4 0
3 years ago
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