Of the five salts listed below, which has the highest concentration of its cation in water? assume that all salt solutions are s
aturated and that the ions do not undergo any additional reactions in water.
1 answer:
First of all, I need to know what these five salts are. Luckily, I found a similar problem from another website which is shown in the attached picture. The Ksp is the solubility product constant. It follows the formula:
Ksp = [cation concentration]ᵃ[anion concentration]ᵇ
where a and b are the subscripts of the metal and nonmetal, respectively.
For the solutions ahead, let x be the concentration of the cation.
A. The formula is PbCr₂O₄.
2.8×10⁻¹³ = [x][x]
Solving for x, x = 5.29×10⁻⁷ M
B. The formula is Co(OH)₂.
1.3×10⁻¹⁵ = [x][x]²
Solving for x, x = 1.09×10⁻⁵ M
C. The formula is CoS.
5×10⁻²² = [x][x]
Solving for x, x = 2.24×10⁻¹¹ M
D. The formula is Cr(OH)₃.
1.6×10⁻³⁰ = [x][x]³
Solving for x, x = 3.56×10⁻⁶ M
E. The formula is Ag₂S.
6×10⁻⁵¹ = [x]²[x]
Solving for x, x = 1.82×10⁻¹⁷ M
<em>Thus,the highest concentration is letter B, Cobalt (II) Hydroxide.</em>
Ksp = [cation concentration]ᵃ[anion concentration]ᵇ
where a and b are the subscripts of the metal and nonmetal, respectively.
For the solutions ahead, let x be the concentration of the cation.
A. The formula is PbCr₂O₄.
2.8×10⁻¹³ = [x][x]
Solving for x, x = 5.29×10⁻⁷ M
B. The formula is Co(OH)₂.
1.3×10⁻¹⁵ = [x][x]²
Solving for x, x = 1.09×10⁻⁵ M
C. The formula is CoS.
5×10⁻²² = [x][x]
Solving for x, x = 2.24×10⁻¹¹ M
D. The formula is Cr(OH)₃.
1.6×10⁻³⁰ = [x][x]³
Solving for x, x = 3.56×10⁻⁶ M
E. The formula is Ag₂S.
6×10⁻⁵¹ = [x]²[x]
Solving for x, x = 1.82×10⁻¹⁷ M
<em>Thus,the highest concentration is letter B, Cobalt (II) Hydroxide.</em>
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Hello!
The Chemical reaction is the following:
2F₂(g) + 2 H₂O(g) → O₂(g) + 4HF(g)
If we assume that all the gases are ideal gases, we can describe the coefficients of this reaction as Volume rather than moles, so we can apply the following equations:
So, 2 L of Water Vapor reacts with the fluorine; and 1 L of Oxygen and 4 L of Hydrogen Fluoride are produced.
Have a nice day!
The Chemical reaction is the following:
2F₂(g) + 2 H₂O(g) → O₂(g) + 4HF(g)
If we assume that all the gases are ideal gases, we can describe the coefficients of this reaction as Volume rather than moles, so we can apply the following equations:
So, 2 L of Water Vapor reacts with the fluorine; and 1 L of Oxygen and 4 L of Hydrogen Fluoride are produced.
Have a nice day!
Answer:
The electronic configuration of the magnesium atom shows that it has two unpaired outermost shell electrons while that of oxygen shows that it has six outermost shell electrons with two of them unpaired.
By means of elecron transfer, magnesium atom donates its two electrons to the oxygen atom to now have a charge of +2 while the oxygen then has a charge of -2. This results in an ionic bonding between the two atoms.
Explanation:
The structure is found in the attachment below
