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Nataly [62]
2 years ago
12

A particle accelerates from rest with an acceleration of 8.0m/s2. Calculate its velocity after 150s. What kinematic formula must

be used to solve this problem?
Sample answer format: c=a+b (no spaces in between). If subscript is needed type it as it is , for example cf=ai+b.
Chemistry
2 answers:
skad [1K]2 years ago
7 0

Answer:

v = u + at

Explanation:

Substitute the values and get the answer.

I have also listed variables and values with reference to this question.

v = final velocity = ?

u = initial velocity = 0

a = acceleration = 8

t = time taken = 150

Hope it helps :)

Ipatiy [6.2K]2 years ago
4 0

<u>Answer</u>:

Final velocity: 1200 m/s

<u>Explanation</u>:

Formula:   \overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}

<u>Where</u>:

a = average acceleration

v = final velocity

vo = starting velocity

t = elapsed time

<em>Here the final velocity is unknown which we have to find. The initial is 0 m/s</em>

<em>as it was at rest. The time taken: 150 seconds. Acceleration given 8.0 m/s²</em>

using the formula:

\overline{a} = \frac{v - v_0}{t}

8 = \frac{v - 0}{150}

v = 1200 m/s

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According to the Raoult's law,

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p_{He}=0.554\times 5.78atm=3.20atm

Thus, the partial pressure of CH_4,CO_2 and He gases are, 1.54, 1.03 and 3.20 atm respectively.

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