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Nataly [62]
2 years ago
12

A particle accelerates from rest with an acceleration of 8.0m/s2. Calculate its velocity after 150s. What kinematic formula must

be used to solve this problem?
Sample answer format: c=a+b (no spaces in between). If subscript is needed type it as it is , for example cf=ai+b.
Chemistry
2 answers:
skad [1K]2 years ago
7 0

Answer:

v = u + at

Explanation:

Substitute the values and get the answer.

I have also listed variables and values with reference to this question.

v = final velocity = ?

u = initial velocity = 0

a = acceleration = 8

t = time taken = 150

Hope it helps :)

Ipatiy [6.2K]2 years ago
4 0

<u>Answer</u>:

Final velocity: 1200 m/s

<u>Explanation</u>:

Formula:   \overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}

<u>Where</u>:

a = average acceleration

v = final velocity

vo = starting velocity

t = elapsed time

<em>Here the final velocity is unknown which we have to find. The initial is 0 m/s</em>

<em>as it was at rest. The time taken: 150 seconds. Acceleration given 8.0 m/s²</em>

using the formula:

\overline{a} = \frac{v - v_0}{t}

8 = \frac{v - 0}{150}

v = 1200 m/s

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Calculate the standard molar enthalpy for the complete combustion of liquid ethanol (C2H5OH) using the standard enthalpies of fo
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Answer:

Explanation:

For the reaction

C2H5OH (l) + 3 O2(g) = 2CO2(g) + 3 H2O

We can calculate the  standard molar enthalpy of combustion using the standard enthalpies of formation of the species involved in the reaction according to Hess law:

ΔHºc =  2ΔHºf CO2 (g) + 3ΔHºfH2O(l)  - ( ΔHºf C2H5OH (l) - 3ΔHºfO2 (g) )

( we were not give the water state but we know we are at standard conditions so it is in its liquid state )

The ΔHºfs can be found in appropiate reference or texts.

ΔHºc =  2ΔHºf CO2 (g)+ 3ΔHºfH2O(l)  - (  ΔHºf C2H5OH (l) -+3ΔHºfO2 (g) )

= [ 2 ( -393.52 ) + 3 ( -285.83 ) ] - [(  -276.2 + 0 ) ] kJ

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5 0
3 years ago
a compound with the empirical formula CH2 has a molar mass of 112 g/mol. What is the molecular formula for this compound?
miv72 [106K]
Hope it cleared your doubt :-D

5 0
3 years ago
N2H4 + N2O4 --&gt; N2 + H2O
ahrayia [7]

Answer:

  1. The limiting reagent is N2O4
  2. 14,09g

Explanation:

  • First, we adjust the reaction.

2N_{2} H_{4} + N_{2} O_{4} ⇄6N_{2} +  4H_{2}O

  • Second, we assume that the participating moles are equal to the stoichiometric ratios because we do not know the amounts of the reagents.

We can determinate what is the limiting reagent comparing of product amounts which can be formed from each reactant.

Using N_{2} H_{4} to form H_{2}O

               molH_{2} O = 1mol N_{2} H_{4} } . \frac{4 mol H_{2} O}{2mol N_{2} H_{4} }. \frac{18\frac{g}{mol}  H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}H_{4}  }{32,04\frac{g}{mol}  N_{2} H_{4} }

                                           molH_{2} O = 1, 125 mol

Using N_{2} O_{4} to form H_{2} O

              molH_{2} O = 1mol N_{2} O_{4} } . \frac{4 mol H_{2} O}{1mol N_{2} O_{4} }. \frac{18\frac{g}{mol}  H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}O_{4}  }{92\frac{g}{mol}  N_{2} O_{4} }

                                           molH_{2} O = 0,783 mol

The limiting reagent is N2O4, because can produce only 0, 783 mol of H2O.

This is the minimum measure can be formed of each product.

∴                          MassOfH_{2}O = 0,783mol . 18\frac{g}{mol}

                                      MassOfH_{2}O = 14,09g

5 0
3 years ago
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Svetach [21]

Answer : The correct option is, 1s^22s^22p^63s^23p^64s^23d^{10}4p^5

Explanation :

The given element bromine belongs to the group 17 and period 4. The symbol of bromine is, Br.

The atomic number of bromine = 35

The total number of electrons present in bromine element = 35

Electronic configuration : It is defined as the arrangement of electrons around the nucleus of an atom.

Hence, the correct electronic configuration of bromine is,

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8 0
3 years ago
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