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Nataly [62]
3 years ago
12

A particle accelerates from rest with an acceleration of 8.0m/s2. Calculate its velocity after 150s. What kinematic formula must

be used to solve this problem?
Sample answer format: c=a+b (no spaces in between). If subscript is needed type it as it is , for example cf=ai+b.
Chemistry
2 answers:
skad [1K]3 years ago
7 0

Answer:

v = u + at

Explanation:

Substitute the values and get the answer.

I have also listed variables and values with reference to this question.

v = final velocity = ?

u = initial velocity = 0

a = acceleration = 8

t = time taken = 150

Hope it helps :)

Ipatiy [6.2K]3 years ago
4 0

<u>Answer</u>:

Final velocity: 1200 m/s

<u>Explanation</u>:

Formula:   \overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}

<u>Where</u>:

a = average acceleration

v = final velocity

vo = starting velocity

t = elapsed time

<em>Here the final velocity is unknown which we have to find. The initial is 0 m/s</em>

<em>as it was at rest. The time taken: 150 seconds. Acceleration given 8.0 m/s²</em>

using the formula:

\overline{a} = \frac{v - v_0}{t}

8 = \frac{v - 0}{150}

v = 1200 m/s

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Answer:

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<em>The empirical formula is Ag2O.Explanation:</em>

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6 0
3 years ago
Read 2 more answers
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weqwewe [10]

Answer:

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Explanation:

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H₂(g) + I₂(g) ⇌ 2 HI(g)

Expression for Kc = [HI]² / [H₂] .  [I₂]            54.3

We analyse the equation:

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Initially   0.00623      0.00414              0.0424

React            x                  x                        2x

x amount has reacted, therefore by stoichiometry 2x has been added to the HI, that we have in the beginning.

Eq         0.00623-x    0.00414-x             0.0424+2x

We make the expression for Kc:

Kc = (0.0424+2x)² / (0.00623-x) . (0.00414-x)  = 54.3

This is quadractic funcion:

54.3 = (1.79×10⁻³ + 0.1696x + 4x²) / (2.58×10⁻⁵- 0.01037x + x²)          

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8 0
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