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timofeeve [1]
3 years ago
14

If your unknow solid has an impurity that is insoluble in cyclohexane, will this impurity result in the molar mass of the unknow

n solid being recorded as high, low, or unaffected? Explain.
Chemistry
1 answer:
ser-zykov [4K]3 years ago
5 0

Answer:

High

Explanation:

When the unknown compound contains an impurity that is insoluble in cyclohexane, the solute will not dissolve in the solvent (cyclohexane) completely. ∆T of the solution would be smaller than it is supposed to be, when compared to a compound without such insoluble impurity. Molecular weight determination won't be accurate because the molecular weight obtained will be higher as a result of the fact that the mass of the solute would include the actual solute that is changing the temperature and the excess mass of the impurity.

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A gas occupies 50.0mL at a standard temp. What volume would it occupy at 335 Celsius with
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Answer:

V₂ = 111.3 mL

Explanation:

Given data:

Initial volume of gas = 50.0 mL

Initial temperature = standard = 273.15 K

Final volume = ?

Final temperature = 335 °C (335+273.15 = 608.15 K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 50.0  mL ×608.15 K / 273.15 k

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For work to be done on an object:
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Answer:

The object has to move a distance when a force is applied to it

Explanation:

For work to be done on a body the force applied must move the body through a particular distance.

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If no distance is moved by the force, no work is done.

Also, the angle between the force and the distance must be 0 to do the maximum work on the body.

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3 years ago
when carbon is burned in the air, it reacts with oxygen to form carbon dioxide. when 22.8 g of carbon were burned in the presenc
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Answer:

So there is83.6g CO2 produced

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C + O2 → CO2

For 1 mol Carbon, we have 1 mol O2 and 1 mol CO2

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1.9 mole C will completely react

Since for each mole C there is 1 mole O2 and 1 mole CO2

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mass CO2 = 1.9 mole CO2 * 44g/mole =<u>83.6g CO2</u>

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