1. KI
2. AlBr₃
3. CsNO₃
4. Al₂(CO₃)₃
Explanation:
1. potassium (K⁺) iodine (I⁻) - KI
2. aluminium (Al³⁺) bromine (Br⁻) - AlBr₃
3. caesium (Cs⁺) nitrate (NO₃⁻) - CsNO₃
4. aluminum (Al³⁺) carbonate (CO₃²⁻) - Al₂(CO₃)₃
Learn more about:
formulas for the ionic compounds
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Answer:
0.0184
Explanation:
Let's consider the following reaction at equilibrium.
2 HI(g) ⇌ H₂(g) + I₂(g)
The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.
Kc = [H₂] × [I₂] / [HI]²
Kc = (4.78 × 10⁻⁴) × (4.78 × 10⁻⁴) / (3.52 × 10⁻³)²
Kc = 0.0184
Answer:
14.68 moles of He
Explanation:
To do this, just remember Avogadro's Constant or Avogadro's number. This constant tells us how many units ( in this case atoms) there are in a mole of ANY type of substance.
Avogadro's constant is 6.022140857 × 10²³ units per mole.
Now that we know how many atoms there are in 1 mole, we can use this as our conversion factor.
8.84 x 10²⁴ atoms of He → moles of He
So the answer would be:
14.68 moles of He
They are all equal to one mole (all of the above).
