Answer:
The y-component of the normal force is 45.74 N.
Explanation:
Given that,
Mass of the crate, m = 5 kg
Angle with hill, 
We need to find the y component of the normal force. We know that the y component of the normal force is given by :
So, the y-component of the normal force is 45.74 N. Hence, this is the required solution.
Answer:
H = 1/2 * g * t^2 since initial velocity is zero
v = g * t where v is the final velocity
t = v / g
H = 1/2 g * v^2 / g^2 = 1/2 v^2 / g
v = (2 * H * g)^1.2
v = (2 * 500 * 9.8)^1/2 = 99 m/s
Check: t = v / g = 99 / 9.8 = 10.1 sec
H = 1/2 * 9.8 * 10.1^2 = 500 m
A because the earth have four season and four name for its tilt around the sun. one aphelion prehelion but spring and fall is balance. when its summer in the north it is cold in the south because of son rays
Is the energy contained in the particles of a medium
Answer:
a) 520m
b) 10.30 s
c) 100,95 m/s
Explanation:
a) According the given information, the rocket suddenly stops when it reach the height of 520m, because the engines fail, and then it begins the free fall.
This means the maximum height this rocket reached before falling was 520 m.
b) As we are dealing with constant acceleration (due gravity) 
we can use the following formula:
(1)
Where:
is the initial height of the rocket (at the exact moment in which it stops due engines fail)
is the final height of the rocket (when it finally hits the launch pad)
is the initial velocity of the rocket (at the exact moment in which it stops the velocity is zero and then it begins to fall)
is the acceleration due gravity
is the time it takes to the rocket to hit the launch pad
Clearing :
(2)
(3)
(4)
(5) This is the time
c) Now we need to find the final velocity 
for this rocket, and the following equation will be perfect to find it:
(6)
(7)
(8) This is the final velocity of the rocket. Note the negative sign indicates its direction is downwards (to the launch pad)
