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hram777 [196]
2 years ago
6

Help me with the following problem

Physics
1 answer:
bagirrra123 [75]2 years ago
3 0

The power dissipated in the 6 ohms resistor is determined as 24 W and the power dissipated in the 3 ohms resistor is determined as 48 W.

<h3>Power dissipated in the resistors</h3>

The power dissipated in the resistors is calculated as follows;

P = IV

where;

  • I is current
  • V is voltage = 12 V

From Ohm's law, V = IR, ⇒ I = V/R

P = V²/R

where;

  • R is resistance of the circuit
<h3>Power dissipated in 6 ohms </h3>

P = (12)²/6

P = 24 W

<h3>Power dissipated in 3 ohms</h3>

P = (12)²/3

P = 48 W

Learn more about power here: brainly.com/question/13881533

#SPJ1

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The block in the figure below has a mass of 5.1 kg and it rests on an incline of angle . You pull on the rope with a force F = 3
viktelen [127]

42.9°

Explanation:

Let's assume that the x-axis is aligned with the incline and the positive direction is up the incline. We can then apply Newton's 2nd law as follows:

x:\;\;\;\;F - mg\sin{\theta} = 0\;\;\;\;

\Rightarrow mg\sin{\theta} = F

Note that the net force is zero because the block is moving with a constant speed when the angle of the incline is set at \theta. Solving for the angle, we get

\sin{\theta} = \dfrac{F}{mg}

or

\theta = \sin^{-1}\left(\dfrac{F}{mg}\right)

\;\;\;=  \sin^{-1}\left[\dfrac{34\:\text{N}}{(5.1\:\text{kg})(9.8\:\text{m/s}^2)}\right]

\;\;\;=42.9°

6 0
2 years ago
A 35 N force makes a 10 degree angle with the positive x-axis. What is the magnitude of the vertical component of the force?
Snowcat [4.5K]

Answer:

6.07 N

Explanation:

Given that,

Force, F = 35 N

It makes 10 degree angle with the positive x-axis.

We need to find the magnitude of the vertical component of the force. It can be given by :

F_y=F\sin\theta\\\\=35\times \sin(10)\\\\=6.07\ N

So, the magnitude of the vertical component of the force is 6.07 N.

5 0
3 years ago
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I need help with this. I think I got it correct, but I wanna make sure.
kicyunya [14]

Answer:

A because the bigger it is the the more force needs to act apond it

Explanation:

3 0
3 years ago
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A 3.3 kg ball sits on the ground and is kicked with a FAPP of 36N
jeyben [28]

a) 32.3 N

The force of gravity (also called weight) on an object is given by

W = mg

where

m is the mass of the object

g is the acceleration of gravity

For the ball in the problem,

m = 3.3 kg

g = 9.8 m/s^2

Substituting, we find the force of gravity on the ball:

W=(3.3)(9.8)=32.3 N

b) 48.3 N

The force applied

F_{app} = 36 N

The ball is kicked with this force, so we can assume that the kick is horizontal.

This means that the applied force and the weight are perpendicular to each other. Therefore, we can find the net force by using Pythagorean's theorem:

F=\sqrt{W^2+F_{app}^2}

And substituting

W = 32.3 N

Fapp = 36 N

We find

F=\sqrt{32.3^2+36^2}=48.3 N

c) 14.6 m/s^2

The ball's acceleration can be found by using Newton's second law, which states that

F = ma

where

F is the net force on an object

m is its mass

a is its acceleration

For the ball in this problem,

m = 3.3 kg

F = 48.3 N

Solving the equation for a, we find

a=\frac{F}{m}=\frac{48.3}{3.3}=14.6 m/s^2

8 0
3 years ago
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