Help me with the following problem

Physics

1 answer:

bagirrra123 [75]2 years ago

3 0

The power dissipated in the 6 ohms resistor is determined as 24 W and the power dissipated in the 3 ohms resistor is determined as 48 W.

<h3>Power dissipated in the resistors</h3>

The power dissipated in the resistors is calculated as follows;

P = IV

where;

I is current
V is voltage = 12 V

From Ohm's law, V = IR, ⇒ I = V/R

P = V²/R

where;

R is resistance of the circuit

<h3>Power dissipated in 6 ohms </h3>

P = (12)²/6

P = 24 W

<h3>Power dissipated in 3 ohms</h3>

P = (12)²/3

P = 48 W

Learn more about power here: brainly.com/question/13881533

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