Question

Help me with the following problem

Answer 1

The power dissipated in the 6 ohms resistor is determined as 24 W and the power dissipated in the 3 ohms resistor is determined as 48 W.

Power dissipated in the resistors

The power dissipated in the resistors is calculated as follows;

P = IV

where;

• I is current
• V is voltage = 12 V

From Ohm's law, V = IR, ⇒ I = V/R

P = V²/R

where;

• R is resistance of the circuit

Power dissipated in 6 ohms

P = (12)²/6

P = 24 W

Power dissipated in 3 ohms

P = (12)²/3

P = 48 W

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