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horrorfan [7]
3 years ago
14

Without actually calculating the cubs, find the value of ( 27) ³ +(-15) +(+12) ³​

Mathematics
2 answers:
Vika [28.1K]3 years ago
5 0

<em>(</em><em>2</em><em>7</em><em>)</em><em>^</em><em>3</em><em>+</em><em>(</em><em>-</em><em>1</em><em>5</em><em>)</em><em>+</em><em>(</em><em>1</em><em>2</em><em>)</em><em>^</em><em>3</em>

<em>=</em><em> </em><em>2</em><em>7</em><em>×</em><em>2</em><em>7</em><em>×</em><em>2</em><em>7</em><em>-</em><em>1</em><em>5</em><em>+</em><em>1</em><em>2</em><em>×</em><em>1</em><em>2</em><em>×</em><em>1</em><em>2</em>

= <em>1</em><em>9</em><em>6</em><em>8</em><em>3</em><em>-</em><em>1</em><em>5</em><em>+</em><em>1</em><em>7</em><em>2</em><em>8</em>

<em>=</em><em> </em><em>2</em><em>1</em><em>3</em><em>9</em><em>6</em><em> </em><em> </em><em>answer</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

Sati [7]3 years ago
3 0

(27)³ + (-15)³ + (12)³

Let, x = 27, y = -15, z = 12

Then, x + y + z = 27 - 15 + 12 = 0

We know the algebraic identity, if a + b + c = 0 then a³ + b³ + c³ = 3abc

Thus, (27)³ + (-15)³ + (12)³ = 3×(27)(-15)(12)

= <u>-14580</u><u> </u>

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