Answer:
Secondary current is 8A
Explanation:
Data :
Primary supply = Vp = 240 V
Secondary supply = Vs = 60V
Primary current = Ip = 2A
Secondary current = Is = ?
Formula : Vp × Ip = Vs × Is
So for secondary current formula becomes
Is = (Vp/Vs)×Ip = (240/60) × 2
Is = 4 × 2 = 8A
Dr. Berenson's study showed that when obese children reach adulthood they are 8 times more likely to develop high blood pressure than healthy weight children.
<h3>Dr. Berenson</h3>
Dr. Berenson (September 19, 1922 – November 22, 2018) was an American cardiologist, heart researcher, and public health expert who specialised in determining the root causes of cardiac conditions. According to Dr. Berenson's foundational research, childhood routines and habits are the root cause of adult heart disease. He also found that compared to people with no cardiovascular risk factors, those with three or four cardiovascular risk factors had atherosclerosis that was noticeably more evident. Dr. Berenson began teaching at Tulane University after being released from the U.S. Navy in 1948. He started a two-year research fellowship at the University of Chicago in 1952, where Dr. Berenson worked on rheumatic fever investigations with Albert Dorfman, the department's chief.
According to dr. berenson's study, when obese children reach adulthood, how many times more likely are they have high-blood pressure?
Learn more about dr. Berenson here:
brainly.com/question/21824136
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Answer:
True a, c and d
Explanation:
The correct statements that should be included in the answers are:
a) True. Bowling balls are round
b) False. The balls have different colors
c) True. If the balls are made of a very hard material
d) True. If the balls have a smooth polished surface at the same time, but not soft
In a closed system, energy in form of heat (work) can be exchanged but not matter.
The answer to your question is C.
Hope it helped!
<span>Answer:
Using 1/f = 1/d' + 1/d ...(where d' object distance and d is image distance)
1/4 = 1/7 + 1/d
1/4 - 1/7 = 1/d
3/28 = 1/d
d = 28/3
d = 9.33 cm</span>