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posledela
3 years ago
9

Which position-time graph matches the velocity-time graph?

Physics
1 answer:
lana [24]3 years ago
6 0
B is the answer because the area between the velocity time graph and the x-axis is the distance traveled. If you look at the velocity time graph from 0-2, seconds you will see an area of 40m. Only choice B matches that at 2 seconds, the distance traveled is 40m. You can go on to confirm the remaining trip matches that of B by calculating the 2-4 seconds of the velocity time graph area between the x-axis and graph as -40m (negative because area is under the x-axis). Again, it matches graph B, showing that the total distance traveled is 0 for the entire trip.
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A proton travels at a velocity of 3.0x10^6 m/s in a direction perpendicular to a uniform magnetic field.
Virty [35]

Answer:

0.239 T

Explanation:

Applying,

F = Bvqsin∅................ Equation 1

Where F = magnetic force, B = magnetic Field, q = charge of a proton, v = velocity of proton, ∅ = angle between the velocity and the magnetic field.

make B the subject of the equation

B = F/(vqsin∅)................. Equation 2

From the question,

Given: F = 1.15×10⁻¹³ N, v = 3.0×10⁶ m/s, ∅ = 90°(perpendicular)

Constant: q = 1.602 x 10⁻¹⁹ C

Substitute into equation 2

B =  1.15×10⁻¹³ /(3.0×10⁶×1.602 x 10⁻¹⁹×sin90°)

B = 1.15×10⁻¹³/(4.806×10⁻¹³)

B = 0.239 T.

Hence the magnetic field = 0.239 T

7 0
3 years ago
Where should be the best fit line be drawn on a scatterplot?
eimsori [14]

A line of best fit is a straight line drawn through the most points on a scatter plot, with an equal number of points above and below the line. It is used to investigate the nature of the relationship between two variables. The correct option is d.

<h3>What is line of best fit?</h3>

A straight line with the best fit is one that minimizes the distance between it and some data.

In a scatter plot of varying data points, the line of best fit is used to express a relationship. It is a result of regression analysis and can be used to forecast indicators and price movements.

It is important to note that your line does not need to pass through any of the points on the plot; it only needs to bisect the area that contains the data points.

Thus, none of the options are correct, the correct one is d.

For more details regarding line of best fit, visit:

brainly.com/question/14279419

#SPJ1

8 0
1 year ago
Set up a parallel circuit with three resistors. Set up the battery to be 9 V, one resistor at 10 Ohms, the other at 21 Ohms, and
valina [46]

In a parallel circuit, the equivalent resistance is the reciprocal of (the sum of the individual reciprocals).

1/R = 1/10 + 1/21 + 1/13

1/R = 0.225 mhos

R = 4.45 ohms

I = V / R

The total current out of the battery is

I = (9v)/(4.45ohms)

I = 2.02 Amperes

As the total current leaves the battery, it splits into 3 paths, and each resistor gets part of it. The 10ohm resistor gets the most current; the 21ohm resistor gets the least current. After flowing through the resistors, the 3 currents join and add up to 2.02 Amperes again, and the same current returns to the battery.

Each resistor has the same 9v of EMF across it.

4 0
3 years ago
To reach its intended destination on time a cruise ship needs to travel north at 70 mph. However, it is travelling in the Gulf o
bogdanovich [222]

Answer:

speed is 81.03 mph

direction is N 3.58 W

Explanation:

given data

travel north = 70 mph

Stream current = 12 mph

direction = S 25° E

result due north = 70 mph

to find out

speed and direction

solution

we will get component of resultant  that is

v cosθ  and v sinθ

so

( 12cos295 , 12 sin295 )    at ( 0, 70)

as that we can say

v sinθ + 12sin295 = 70      ....................1

v cosθ + 12 cos295  = 0     ......................2

so

vcosθ  = -5.0714

vsinθ = 80.8756

now by ratio

cosθ /sinθ  = -5.0714/ 80.8756

cot θ = -0.0627

θ = 93.58

so direction is N 3.58 W

and

we know

vcosθ  = - 12cos295

v = - 12cos295 / cos(93.58)

v = 81.03 mph

so speed is 81.03 mph

4 0
3 years ago
A sprinter in a 100-m race accelerates uniformly for the first 71 m and then runs with constant velocity. The sprinter’s time fo
adoni [48]

Answer:

The acceleration of the sprinter is 1.4 m/s²

Explanation:

Hi there!

The equation of position of the sprinter is the following:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the sprinter at a time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

Since the origin of the frame of reference is located at the starting point and the sprinter starts from rest, then, x0 and v0 are equal to zero:

x = 1/2 · a · t²

At t = 9.9 s, x = 71 m

71 m = 1/2 · a · (9.9 s)²

2 · 71 m / (9.9 s)² = a

a = 1.4 m/s²

The acceleration of the sprinter is 1.4 m/s²

3 0
4 years ago
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