Answer:
Explanation:
We shall represent the velocity of cruise ship and coast guard petrol boat in vector form .
velocity of cruise ship
Vcs = - 2.5 j
Vpb = - 4.8 cos 19 i + 4.8 sin 19 j = - 4.54 i + 1.56 j
velocity of the cruise ship relative to the patrol boat
= Vcs - Vpb
= - 2.5 j - ( - 4.54 i + 1.56 j )
= - 2.5 j + 4.54 i - 1.56 j
= 2.04 i - 1.56 j .
x-component of the velocity of the cruise ship relative to the patrol boat
= 2.04 m /s
y-component of the velocity of the cruise ship relative to the patrol boat
= - 1.56 m /s .
Equation 1 :
m1 : m1a =T
Equation 2:m2 : m2a= F - T
Adding 1 and 2a=0.073
Placing in equation 1
we get T = 218.18N
The correct answer to this question is false
