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andreev551 [17]
3 years ago
6

The concentration of a dilute aspirin solution is 0.000529 m. standard solutions of this compound were used to prepare a beer\'s

law plot which gives a slope of 1550.7 m-1. what is the expected absorbance value for the aspirin solution?
Chemistry
1 answer:
slamgirl [31]3 years ago
5 0
<span>From Beer-Lambert's law' A = ECl Since the slope is 1550.7 thus A = 1550.7* 0.000529 M = 0.8203203 Since A = Log (Io/I) and T% = I/Io * 100% Io/I = AntiLog(A) and hence T% = { 1/ AntiLog (A) } *100% T%={1/AntiLog 0.8203203)*100% T%=0.8601654108*100% T%= .860</span>
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Question 2
Thepotemich [5.8K]

Answer:

1-Pentene

Explanation:

If we look at all the options listed, we will notice that the rate of reaction of bromine with each one differs significantly.

For 1-pentene, addition of bromine across the double bond is a relatively fast process. It is usually used as a test for unsaturation. Bromine water is easily decolorized by alkenes.

Cyclohexane, heptane are alkanes. They can only react with chlorine in the presence of sunlight. This is a substitution reaction. It does not occur easily. A certain quantum of light is required for the reaction to occur.

For benzene, bromine can only react with it by electrophilic substitution in which the benzene ring is retained. A Lewis acid is often required for the reaction to occur and it doesn't occur easily.

3 0
3 years ago
Proportional means that
FromTheMoon [43]
Corresponding in size or amount to something else.
5 0
3 years ago
1-Bromopropane is treated with each of the following reagents. Draw the major substitution product if the reaction proceeds in g
sammy [17]

Answer:

Explanation:

If we look at the structure of 1-Bromopropane; we will see that it is a derivative of alkane family by the the substitution of an alkyl group. The position of the Bromine in the propane is 1, making 1-Bromopropane  a primary alkyl-halide.

Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used  otherwise it will result to a reactive mechanism if a weak electrophile is used.

However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.

The attached diagrams portraying this notions is shown in the attached file below.

5 0
3 years ago
the double bond in ethene is made up of a pi bond and a sigma bond formed by lateral overlap of two p orbitals
Deffense [45]

The unhybridized pz orbitals on each carbon overlap to a π bond (pi).The sigma bond framework of the ethylene molecule is produced by the overlap of hybrid orbitals or by the interaction of a hybrid orbital and a 1s hydrogen orbital.

Each carbon still has its unhybridized pz orbital, though. Sigma bond are typically the only types of single bonding between atoms. One sigma bond and two pi bonds make up triple bonds. One sigma () bond makes up a single bond, one and one pi () bond makes up a double bond, and one and two bonds make up a triple bond.

To learn more about bond, click here.

brainly.com/question/10777799

#SPJ4

3 0
2 years ago
three molecules of oxygen react with four molecules of hydrogen to produce water molecules write a balanced chemical equation
mixer [17]

Answer:

ExpC

H

4

+  

2

O

2

 

→

 

C

O

2

+  

2

H

2

O

This is the balanced reaction equation for the combustion of methane.

Explanation:

The Law of Conservation of Mass basically states that matter can neither be created nor destroyed. As such, we must be able to show this in our chemical reaction equations.

If you look at the equation above, you'll see an arrow that separates the reaction equation into two parts. This represents the direction of the reaction.

To the left of the arrow, we have our reactants.

To the right of the arrow, we have our products.

The quantity of each individual element in the left must equal the quantity of each individual element in the right.

So if you look below, you'll see the unbalanced equation, and I'll try to explain how to balance the reaction.

C

H

4

+  

O

2

 

→

 

C

O

2

+  

H

2

O

Our reactants in this equation are  

C

H

4

and  

O

2

.

Our next step is to break these down into individual atoms.

We have:

1 C atom, 4 H atoms & 2 O atoms.

If you're confused by this, look to see the little number to the bottom right of each element, the subscript, and it tells you how many of each atom are in the molecule. Make sense?

Now we look to the other side of the equation.

Here we see our products are  

C

O

2

+  

H

2

O

Again, we break these down into individual atoms again.

We have:

1 C atom, 2 H atom, 3 O atom

6 0
3 years ago
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