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andreev551 [17]
3 years ago
6

The concentration of a dilute aspirin solution is 0.000529 m. standard solutions of this compound were used to prepare a beer\'s

law plot which gives a slope of 1550.7 m-1. what is the expected absorbance value for the aspirin solution?
Chemistry
1 answer:
slamgirl [31]3 years ago
5 0
<span>From Beer-Lambert's law' A = ECl Since the slope is 1550.7 thus A = 1550.7* 0.000529 M = 0.8203203 Since A = Log (Io/I) and T% = I/Io * 100% Io/I = AntiLog(A) and hence T% = { 1/ AntiLog (A) } *100% T%={1/AntiLog 0.8203203)*100% T%=0.8601654108*100% T%= .860</span>
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a metal spoon left in boiling water

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Explanation:

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In the following reaction, 451.4 g of lead reacts with excess oxygen forming 365.0 g of lead(II) oxide. Calculate the percent yi
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MM(Pb) : MM(PbO)
=207.21 : 223.20  =  451.4 g : x g

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When the following oxidation–reduction reaction in acidic solution is balanced, what is the lowest whole-number coefficient for
ruslelena [56]

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b. 16, reactant side

Explanation:

Let's consider the following redox reaction.

MnO₄⁻(aq) + I⁻(aq) → Mn²⁺(aq) + I₂(s)

We can balance it using the ion-electron method.

Step 1: Identify both half-reactions

Reduction: MnO₄⁻(aq) → Mn²⁺(aq)

Oxidation: I⁻(aq) → I₂(s)

Step 2: Perform the mass balance, adding H⁺(aq) and H₂O(l) where appropriate

MnO₄⁻(aq) + 8 H⁺(aq) → Mn²⁺(aq) + 4 H₂O(l)

2 I⁻(aq) → I₂(s)

Step 3: Perform the charge balance, adding electrons where appropriate

MnO₄⁻(aq) + 8 H⁺(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l)

2 I⁻(aq) → I₂(s)  + 2 e⁻

Step 4: Multiply both half-reactions by numbers so that the number of electrons gained and lost are equal

2 × (MnO₄⁻(aq) + 8 H⁺(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l))

5 × (2 I⁻(aq) → I₂(s)  + 2 e⁻)

Step 5: Add both half-reactions and cancel what is repeated on both sides

2 MnO₄⁻(aq) + 16 H⁺(aq) + 10 e⁻ + 10 I⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 I₂(s)  + 10 e⁻

The balanced reaction is:

2 MnO₄⁻(aq) + 16 H⁺(aq) + 10 I⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 I₂(s)

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3 years ago
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