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storchak [24]
3 years ago
13

Which layer of the atmosphere is between the mesosphere and the exosphere?

Physics
2 answers:
Llana [10]3 years ago
8 0

Answer:

thermosphere

Explanation:

Alinara [238K]3 years ago
5 0

Answer:

The answer is thermosphere

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HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!
soldi70 [24.7K]
Limestone, Sandstone, and Shale would be the answer.

4 0
3 years ago
A 40.0 kg beam is attached to a wall with a hi.nge and its far end is supported by a cable. The angle between the beam and the c
GalinKa [24]

The magnitude of the force that the beam exerts on the hi.nge will be,261.12N.

To find the answer, we need to know about the tension.

<h3>How to find the magnitude of the force that the beam exerts on the hi.nge?</h3>
  • Let's draw the free body diagram of the system using the given data.
  • From the diagram, we have to find the magnitude of the force that the beam exerts on the hi.nge.
  • For that, it is given that the horizontal component of force is equal to the 86.62N, which is same as that of the horizontal component of normal reaction that exerts by the beam on the hi.nge.

                           N_x=86.62N

  • We have to find the vertical component of normal reaction that exerts by the beam on the hi.nge. For this, we have to equate the total force in the vertical direction.

                           N_y=F_V=mg-Tsin59\\

  • To find Ny, we need to find the tension T.
  • For this, we can equate the net horizontal force.

                           F_H=N_x=Tcos59\\\\T=\frac{F_H}{cos59} =\frac{86.62}{0.51}= 169.84N

  • Thus, the vertical component of normal reaction that exerts by the beam on the hi.nge become,

                    N_y= (40*9.8)-(169.8*sin59)=246.4N

  • Thus, the magnitude of the force that the beam exerts on the hi.nge will be,

                 N=\sqrt{N_x^2+N_y^2} =\sqrt{(86.62)^2+(246.4)^2}=261.12N

Thus, we can conclude that, the magnitude of the force that the beam exerts on the hi.nge is 261.12N.

Learn more about the tension here:

brainly.com/question/28106871

#SPJ1

4 0
1 year ago
Read 2 more answers
A cat, walking along the window ledge of a new york apartment, knocks off a flower pot, which falls to the street 280 feet below
Harlamova29_29 [7]
H = 280 ft, the height of the flower pot.
g = 32 ft/s²

Neglect air resistance.
Note that 1 ft/s = 15/22 mi/h

The initial vertical velocity is zero.
Let v =  the velocity with which the flower pot hits the ground.
Then
v² = 2gh
    = 2*(32 ft/s²)*(280 ft)
    = 17920 (ft/s)²
v = 133.866 ft/s

Also,
v = (133.866 ft/s)*(15/22 (mi/h)/(ft/s)) = 91.272 mi/h

Answer:  133.9 ft/s or 91.3 mi/h

5 0
3 years ago
Candice is examining a cell under a microscope. She has identified a cell wall, a nucleus, and a chloroplast. What type of organ
RoseWind [281]

Answer:

A plant

Explanation:

because animals don't have cell walls, and fungus and bacteria dont have chloroplasts

7 0
3 years ago
Why do some nucleus release electrons?
fredd [130]

Answer:

Electrons are not little balls that can fall into the nucleus under electrostatic attraction

Explanation:

5 0
3 years ago
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