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3 years ago

Which layer of the atmosphere is between the mesosphere and the exosphere?

Physics

2 answers:

Llana [10]3 years ago

8 0

Answer:

thermosphere

Explanation:

Alinara [238K]3 years ago

5 0

Answer:

The answer is thermosphere

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ASAP please!! <br>The force vectors on an aircraft are as shown. Find the net (resultant force).

ioda

Answer:

The magnitude of the net force is 5430N

Explanation:

I suggest to define the axes as aligned to the axis of the plane. This will require you to decompose only one vector, namely the Weight. We need two components of the W force: one in horizontal direction of the plane, the other perpendicular to it. Through a simple triangle argument you will se that the plane-horizontal component of W is

$W_D=3600 N\cdot\sin 27^\circ=1634N$

acting in the direction of the Drag, and the plane-perpendicular component is:

$W_L=-3600N\cdot\cos 27^\circ=-3208N$

with negative sign since it counteracts the Lift.

So the components of the netforce F are:

$F_h=T-D-W_D=(8000-1000-1634)N=5366N\\F_v=L+W_L=(4100-3208)N=829N$

The magnitude of the net force is:

$|F|=\sqrt{5366^2+829^2}N = 5430N$

6 0

3 years ago

Distinguish the difference in mass and weight

levacccp [35]

Ok to distinguish the difference you just find out why there's science lol.......anyways.....Mass is the amount of space being taken up in a certain place (or possibly all the world) and weight is the heaviness of an person or thing kk??? also if my answer was best, plzz give brainliest (trust me i need it) Have a great day and Christmas (if u celebrate it)!!

3 0

3 years ago

A toy of mass 0.155 kg is undergoing simple harmonic motion (SHM) on the end of a horizontal spring with force constant 305 N/m

zzz [600]

Answer:

$310.38\times 10^{-4}j$

Explanation:

We have given mass m=0.155 kg

Force constant K = 305 N/m

Distance $X=1.25\times 10^{-2}m$

Velocity $v=.305 m/sec$

The total energy at any position of the motion is give by $E=\frac{1}{2}mv^2+KX^2$ here $\frac{1}{2}mv^2$ is energy due to motion and $KX^2$ is energy due to spring elongation

So total energy $E=\frac{1}{2}\times 0.155\times 0.305^2+305\times 0.0125^2=310.38\times 10^{-4}j$

4 0

3 years ago

A ball thrown straight up climbs for 3.0 sec before falling. Neglecting air resistance, with what velocity was the ball thrown?

sesenic [268]

Answer:

Speed, u = 29.4 m/s

Explanation:

Given that, A ball thrown straight up climbs for 3.0 sec before falling, t = 3 s

Let u is speed with which the ball is thrown up. When the ball falls, v = 0

Using first equation of motion as :

v = u + at

Here, a = -g

So, u = g × t

$u=9.8\times 3$

u = 29.4 m/s

So, the speed with which the ball was thrown is 29.4 m/s. Hence, this is the required solution.

7 0

4 years ago

A raft of mass 199 kg carries two swimmers of mass 52 kg and 70 kg. The raft is initially floating at rest. The two swimmers sim

Minchanka [31]

To solve this problem we will apply the concept related to the conservation of the Momentum. We will then start considering that the amount of initial momentum must be equal to the amount of final momentum. Considering that all the objects at the initial moment have the same initial velocity (Zero, since they start from rest) the final moment will be equivalent to the multiplication of the mass of each object by the velocity of each object, so

Initial Momentum = Final Momentum

$(m_B+m_1+m_2)v_i = m_1v_1+m_2v_2+m_Bv_B$