A brick 25cm long ,9cm wide 5cm thick has a mass of 1000g determine the greatest pressure that can be exerted by the brick on a
1 answer:
Answer:
<em>The greatest pressure is 2178 Pa</em>
Explanation:
<u>Pressure</u>
It's the force applied perpendicular to the surface of an object per unit area over which the force is distributed.
If F is the force applied and A is the surface area, the pressure is calculated as:
The brick has dimensions of 25 cm by 9 cm by 5 cm. There are three possible areas of contact:
The brick has a mass of m=1000 g = 1 Kg and exerts a force equal to its weight when placed on a flat surface, thus:
F = m.g = 1 * 9.8 = 9.8 N
The greatest possible pressure will occur when the area is the least possible , since the pressure and the area are inversely proportional, thus:
The greatest pressure is 2178 Pa
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To solve this problem we will use the concepts related to Magnification. Magnification is the process of enlarging the apparent size, not physical size, of something. This enlargement is quantified by a calculated number also called "magnification".
The overall magnification of microscope is
Where
N = Near point
l = distance between the object lens and eye lens
= Focal length
= Focal of eyepiece
Given that the minimum distance at which the eye is able to focus is about 25cm we have that N = 25cm
Replacing,
Therefore the correct answer is C.
Answer:
E = 3.54 x 10⁻¹⁹ J
Explanation:
The energy of the photon can be given in terms of its wavelength by the use of the following formula:
where,
E = energy = ?
h = Plank's Constant = 6.626 x 10⁻³⁴ Js
c = speed of light = 2.998 x 10⁸ m/s
λ = wavelength of light = 560.6 nm = 5.606 x 10⁻⁷ m
Therefore,
<u>E = 3.54 x 10⁻¹⁹ J</u>
The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;
a) The maximum speed is v = 4.89 m / s
b) The maximum height is h = 1.22 m
The energy conservation is one of the most fundamental principles of physics, stable that if there are no friction forces the mechanistic energy remains constant. Mechanical energy is the sum of the kinetic energy plus the potential energies.
Em = K + U
Let's write the energy in two points.
Starting point. Highest part of the oscillation
Em₀ = U = m g h
Final point. Lower part of the movement
= K = ½ m v²
Energy is conserved.
Emo =
m g h = ½ m v²
v² = 2 gh
Let's use trigonometry to find the height, see attached.
h = L - L cos θ
h = L (1- cos θ)
They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.
h = 3.7 (1- cos 48)
h = 1.22 m
this is the maximum height of the movement.
Let's calculate the velocity.
v = 4.89 m / s
In conclusion using the conservation of energy and trigonometry we can find the results for the questions about the movement of the acrobat are;
a) The maximum speed is v = 4.89 m / s
b) The maximum height is h = 1.22 m
Learn more here: brainly.com/question/13010190
