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3 years ago

Which coordinate pair identifies the point in the third quadrant of the coordinate plane?

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

7 0

The correct answer is D

MA_775_DIABLO [31]3 years ago

3 0

Answer:

The is answer is D

Step-by-step explanation:

It is because the third quadrant is ( -, - )

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Over a 24-hour period, the tide in a harbor can be modeled by one period of a sinusoidal function. The tide measures 4.35 ft at

netineya [11]

Answer:

f(x) = 4.35 +3.95·sin(πx/12)

Step-by-step explanation:

For problems of this sort, a sine function is used that is of the form ...

f(x) = A + Bsin(2πx/P)

where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.

It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...

f(x) = 4.35 + 3.95·sin(2πx/24)

The argument of the sine function can be simplified to πx/12, as in the Answer, above.

8 0

4 years ago

Answer please if its good then i'll give brainliest

stepladder [879]

There is no question? ...

4 0

3 years ago

Read 2 more answers

At a particular restaurant, each onion ring has 65 calories and each slider has 250 calories. A combination meal with onion ring

andre [41]

Answer:

The number of onion rings is 3 in the combination meal and the number of sliders is 2 in the combination meal.

Step-by-step explanation:

Given:

At a particular restaurant, each onion ring has 65 calories and each slider has 250 calories. A combination meal with onion rings and sliders has a total of 5 onion rings and sliders altogether and contains 695 calories.

Now, to find the number of onion rings in the combination meal and the number of sliders in the combination meal.

Let the number of onion rings in the combination meal be $x.$

And let the number of sliders in the combination meal be $y.$

So, the total number of onion rings and sliders are:

$x+y=5\\\\y=5-x\ \ \ .....(1)$

Now, the total number of calories each onion rings and sliders has:

$x(65)+y(250)=695$

Substituting the value of $y$ from equation (1) we get:

$x(65)+(5-x)(250)=695\\\\65x+1250-250x=695\\\\1250-185x=695$

Subtracting both sides by 1250 we get:

$-185x=-555$

Dividing both sides by -185 we get:

$x=3.$

The number of onion rings in the combination meal = 3.

Now, substituting the value of $x$ in equation (1) we get:

$y=5-x\\\\y=5-3\\\\y=2.$

The number of sliders in the combination meal = 2.

Hence, the number of onion rings is 3 in the combination meal and the number of sliders is 2 in the combination meal.

8 0

3 years ago

Which type(s) of symmetry does the figure have?

WINSTONCH [101]

It has C. Rotational.... 180 degree rotational symmetry

4 0

4 years ago

Read 2 more answers

Given that 2y^3+by-cy+d,where b,c and d are constants,leaves a remainder R when divided by (y+1) , (y-2) and (2y-1). Find the va

Eddi Din [679]

The polynomial remainder theorem says that a polynomial p(x) leaves a remainder of p(k) when it's divided by x - k.

We're given that dividing p(y) = 2y³ + by² - cy + d leaves the same remainder R after dividing it by y + 1, y - 2, and 2y - 1. So we have

p(-1) = 2(-1)³ + b(-1)² - c(-1) + d = R

==> R = -2 + b + c + d

p(2) = 2(2)³ + b(2)² - c(2) + d = R

==> R = 16 + 4b - 2c + d

p(1/2) = 2(1/2)³ + b(1/2)² - c(1/2) + d = R

==> R = 1/4 + b/4 - c/2 + d

We're also given that y + 2 is a factor, which means dividing p(y) by it leaves no remainder, and so

p(-2) = 2(-2)³ + b(-2)² - c(-2) + d = 0

==> 0 = -16 + 4b + 2c + d

Solve the system of equations in boldface. You can eliminate d from the first 3 to first solve for b and c, then solve for d :

(-2 + b + c + d) - (16 + 4b - 2c + d) = R - R

-18 - 3b + 3c = 0

b - c = -6

(-2 + b + c + d) - (1/4 + b/4 - c/2 + d) = R - R

-9/4 + 3b/4 + 3c/2 = 0

b + 2c = 3

(b - c) - (b + 2c) = -6 - 3

-3c = -9

c = 3

b - 3 = -6

b = -3

-16 + 4(-3) + 2(3) + d = 0

d = 22

7 0

3 years ago