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AURORKA [14]
3 years ago
13

Scientist accept ideas of the past and do not try to revise or change them

Physics
1 answer:
Vikentia [17]3 years ago
4 0
Is this a question or a statement. This statement would be incorrect. <span />
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A person running has a momentum of 720 kg m/s and is traveling at a velocity of 5 m/s. What is his mass?
allsm [11]

Explanation:

Momentum is mass times velocity.

p = mv

720 kg m/s = m (5 m/s)

m = 144 kg

7 0
3 years ago
1. What does the term monecious mean?
ValentinkaMS [17]

Answer:

Monecious is a plant or invertebrate animal having both the male and female reproductive organs in the same individual; hermaphrodite.

7 0
2 years ago
120 J of work was done to lift an object 6 m above
Slav-nsk [51]

Answer:

The last option, 20 N and 2.04 kg

Explanation:

work = (force)(distance)

work = 120 joules

distance: 6 m

rearrange to find force:

120=(6)F

F= 120/6 = 20 Newtons.

Assuming its lifted from Earth's surface, the force of gravity will be 9.81 m/s^2. Let's find mass:

F=mg

m=F/g

m=(20)/(9.81)= 2.038 kg

6 0
2 years ago
When you are aware that you are having a dream and can control what you do
lianna [129]

Answer:

D. lucid dreaming

Explanation:

(=^w^=)

6 0
3 years ago
Read 2 more answers
A layer of oil (n = 1.38) floats on an unknown liquid. A ray of light originates in the oil and passes into the unknown liquid.
Vinil7 [7]

Answer:

Refractive index of unknown liquid = 1.56

Explanation:

Using Snell's law as:

n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}

Where,  

{\theta_i}  is the angle of incidence  ( 65.0° )

{\theta_r} is the angle of refraction  ( 53.0° )

{n_r} is the refractive index of the refraction medium  (unknown liquid, n=?)

{n_i} is the refractive index of the incidence medium (oil, n=1.38)

Hence,  

1.38\times {sin65.0^0}={n_r}\times{sin53.0^0}

Solving for {n_r},

Refractive index of unknown liquid = 1.56

4 0
3 years ago
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