Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
Learn more : brainly.com/question/18405415
Snemsjsjsjjsuduwjrbebsjenwnwnwnnnnnnjjjnnjnbbjjokbbkjvgjjbnnnnkkkkkkkkkkkk
Answer:
A
Step-by-step explanation:
Answer:
2 kg
Step-by-step explanation:
15/100 x = 0.3
x = 0.3 * 100/15
x = 2