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Virty [35]
3 years ago
6

A girl stands 5m away from a large plane mirror. How far must she walk to be 2m away from her image?

Physics
1 answer:
lord [1]3 years ago
8 0

Answer:

The girl needs to walk 4m closer to the mirror if she must be 2 m away from her image.

Explanation:

Images formed by plane mirrors is due to reflection of light Plane mirrors form only virtual or imaginary images. The image formed by a plane mirror is equidistant from the mirror as the object is from the mirror. This means that the distance of the girl from the mirror which is 5m is equal to the distance of her image from the mirror.

The distance of the girl from her image when she stands 5 m from the mirror is therefore, 5m + 5m = 10 m

In order for her to be 2 m away from her image, she needs to sand at a distance half her distance from her image, that is 1/2 * 2m = 1m

Therefore, the girl needs to walk 5m - 1m = 4m closer to the mirror if she has to be 2 m away from her image.

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A metabolic waste of algae that can be recycled for use in cellular respiration is
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3 years ago
A 12.0-g plastic ball is dropped from a height of 2.50 m. Just as it strikes the floor, it is moving at a speed of 3.20 m/s. How
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Answer:

0·233 J

Explanation:

Given

Mass of the ball = 0·012 kg

Initially the ball is at a height of 2·5 m

As initially the ball is dropped, it's initial velocity will be equal to 0

Therefore initially it has zero kinetic energy and has only potential energy

∴ Initially total mechanical energy of the ball = potential energy of the ball

Initial potential energy of the ball = m × g × h

where

m is the mass of the ball

g is the acceleration due to gravity

h is the height of the ball

∴ Potential energy = 0·012 × 9·8 × 2·5 = 0·294 J

Velocity of the ball after striking the floor = 3·2 m/s

After striking the floor, the total mechanical energy = kinetic energy just after striking the floor

Kinetic energy = 0·5 × m × v²

where m is the mass of the ball

v is the velocity of the ball

∴ Kinetic energy of the ball = 0·5 × 0·012 × 3·2² = 0·061 J

Mechanical energy that is lost = 0·294 - 0·061 = 0·233 J

∴ Mechanical energy that the ball lost during its fall = 0·233 J

6 0
3 years ago
Where is the most energy transferred in a food web?
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Answer:

is b and d hope id helpful

Explanation:

idk how to explain

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3 years ago
Given a second class lever with a distance of 5.00 feet from the fulcrum to the effort and a distance of 33.0 inches from the re
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Answer:

The correct answer is C. 45.5 lbs.

Explanation:

In a second class lever, the load is located between the point in which the force is exerted and the fulcrum.

The formula for any problem involving a lever is:

F_ed_e=F_ld_l

Where F_e is the effort force, d_e is the total length of the lever, F_l is the load that can be lifted and d_l is the distance between the point of the effort and the fulcrum.

The parameter of the formula that you need is F_l:

F_l=\frac{F_ed_e}{d_l}

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F_l=45.5 lbs

7 0
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