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Virty [35]
3 years ago
6

A girl stands 5m away from a large plane mirror. How far must she walk to be 2m away from her image?

Physics
1 answer:
lord [1]3 years ago
8 0

Answer:

The girl needs to walk 4m closer to the mirror if she must be 2 m away from her image.

Explanation:

Images formed by plane mirrors is due to reflection of light Plane mirrors form only virtual or imaginary images. The image formed by a plane mirror is equidistant from the mirror as the object is from the mirror. This means that the distance of the girl from the mirror which is 5m is equal to the distance of her image from the mirror.

The distance of the girl from her image when she stands 5 m from the mirror is therefore, 5m + 5m = 10 m

In order for her to be 2 m away from her image, she needs to sand at a distance half her distance from her image, that is 1/2 * 2m = 1m

Therefore, the girl needs to walk 5m - 1m = 4m closer to the mirror if she has to be 2 m away from her image.

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Which vector shows the direction of the centripetal acceleration at this point
Mademuasel [1]

Answer:

It's B

Explanation:

6 0
3 years ago
The kinetic energy of a moving object is E=12mv2. A 61 kg runner is moving at 10kmh. However, her speedometer is only accurate t
jek_recluse [69]

Answer:

e=3367.2J

%e=1.43%

Explanation:

From the exercise we know two information. The real speed and the experimental measured by the speedometer

v_{r}=10km/h=2.77m/s

Since the speedometer is only accurate to within 0.1km/h the experimental speed is

v_{e}=10km/h-0.1km/h=9.9km/h=2.75m/s

Knowing that we can calculate Kinetic energy for the real and experimental speed

E_{r}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.77m/s)^2=234023J

E_{e}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.75m/s)^2=230656J

Now, the potential error in her calculated kinetic energy is:

e=E_{r}-E_{e}=(234023-230656)J=3367.2J

%e=\frac{E_{r}-E_{e}}{E_{r}}x100=\frac{(234023-230656)J}{234023J}x100=1.43%

4 0
3 years ago
Difference between freefall and weightlessness.​
Margaret [11]

Answer:

Differences between freefall and weightlessness are as follows:

<h3><u>Freefall</u></h3>
  • When a body falls only under the influence of gravity, it is called free fall.
  • Freefall is not possible in absence of gravity.
  • A body falling in a vacuum is an example of free fall.

<h3><u>Weightlessness</u></h3>
  • Weightlessness is a condition at which the apparent weight of body becomes zero.
  • Weightlessness is possible in absence of gravity.
  • A man in a free falling lift is an example of weightlessness.

Hope this helps....

Good luck on your assignment....

6 0
3 years ago
To turn a coil of wire into a magnet, run a(n) ____ through it.
evablogger [386]

A.) Electromagnetic Current

please mark me as the brainliest

7 0
3 years ago
Read 2 more answers
What is the volume V of a sample of 4.00 mol of copper? The atomic mass of copper (Cu) is 63.5 g/mol, and the density of copper
rusak2 [61]

Answer : The volume of a sample of 4.00 mol of copper is 28.5cm^3

Explanation :

First we have to calculate the mass of copper.

\text{ Mass of copper}=\text{ Moles of copper}\times \text{ Molar mass of copper}

\text{ Mass of copper}=(4.00moles)\times (63.5g/mole)=254g

Now we have to calculate the volume of copper.

Formula used :

Density=\frac{Mass}{Volume}

Now put all the given values in this formula, we get:

8.92\times 10^3kg/m^3=\frac{254g}{Volume}

Volume=\frac{254g}{8.92\times 10^3kg/m^3}=2.85\times 10^{-2}L=2.85\times 10^{-2}\times 10^3cm^3=28.5cm^3

Conversion used :

1kg/m^3=1g/L\\\\1L=10^3cm^3

Therefore, the volume of a sample of 4.00 mol of copper is 28.5cm^3

7 0
3 years ago
Read 2 more answers
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