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vovikov84 [41]
4 years ago
7

11)

Physics
1 answer:
Vikki [24]4 years ago
6 0

Answer:

salt w nulas...........

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Can someone help me with this please?
shutvik [7]

Answer:

Your answer will be C. 3.8 kPa.

7 0
3 years ago
If Sarah melts 10g of tin. What mass of melted tin would she have at the end of the experiment?​
Nastasia [14]

Answer:

10g

Explanation:

As the Law of Conservation of Mass states that " Mass can neither be created nor be destroyed in a chemical reaction".

Though melting of tin isn't a chemical change, the same logic is applied here...

Hence,

The mass of tin will be 10 g itself...

7 0
4 years ago
Read 2 more answers
Bill and Ted are standing on a bridge 40 ft above a river. Bill drops a stone, while Ted decides to throw a stone downward at 10
Y_Kistochka [10]

Answer:

D) - 0.72 secs

Explanation:

Parameters given:

Height of bridge = 40ft = 12.19 m

Initial velocity of Bill's stone = 0m/s

Initial velocity of Ted's stone = 10m/s

We find the time it take Bill's stone to bit the river and the time it takes Ted's stone to hit the river. Then we find the time difference.

Using one of the equations of motion:

For Bill:

S = ut + ½gt²

Where g = 9.8 m/s

12.19 = 0 + ½*9.8*t²

t² = 12.19/4.9 = 2.49

t = 1.58 secs

For Ted:

S = uT + ½gT²

12.19 = 10*T + ½*9.8*T²

=> 4.9T² + 10T - 12.19 = 0

Using quadratic formula and retaining only the positive value, we get that:

T = 0.86 secs

Time difference between Bill's throw and Ted's throw is:

0.86 - 1.58 = - 0.72 secs

In reality, this means that Ted must throw his stone 0.72 secs before Bill throws his for both stones to land the same time.

6 0
4 years ago
Complete the passage to summarize factors affecting the speed of a wave. The material or substance that a wave moves through is
pantera1 [17]

the first one is medium, the second one is type, and the third one is temperature . if i gave the correct answer, please give best answer x

6 0
4 years ago
Read 2 more answers
Starting from rest, your friend dives from a high cliff into a deep lake below, yelling in excitement at the thrill of free-fall
Olegator [25]

Answer:

2 seconds

Explanation:

f = Frequency of yell = 919 Hz

\Delta f = Shifted frequency = 55.9 Hz

v = Speed of sound in air = 342 m/s

v_r = Velocity of friend

a = Acceleration due to gravity = 9.81 m/s²

From the Doppler shift formula we have

\dfrac{f+\Delta f}{f}=\dfrac{v}{v-v_r}\\\Rightarrow v_r=v-\dfrac{vf}{f+\Delta f}\\\Rightarrow v_r=342-\dfrac{342\times 919}{919+55.9}\\\Rightarrow v_r=19.61\ m/s

The velocity of the my friend is 19.61 m/s

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{19.61-0}{9.8}\\\Rightarrow t=2\ s

The time my friend is in the air is 2 seconds

7 0
3 years ago
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