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Vlada [557]
3 years ago
12

Which type of force is used by your legs to pedal a bicycle?

Physics
1 answer:
Kay [80]3 years ago
8 0
The answer is strong push. When you ride a bike, the pedals convert a vertical push from your legs into rotational motion for the wheels to turn.
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Please Help On These 2 Questions!!!!! I severely need help!!!!!!
lys-0071 [83]
3. In a uniform electric field, the equation for the magnitude of the magnetic field is E=(V/d). V= voltage d= distance. If the magnetic field magnitude is constant , as stated in your problem, then the voltage must stay the same otherwise the value of "E" would change". And the problem already told us the "E" is uniform and so, not changing. Does that make sense?

4a. If the magnetic field lines are equally spaced apart, in other words share the same density. Then we know that the magnitude of the magnetic field is unchanging. This is because the density of of the magnetic field lines(how many are in a certain area) is related to the magnitude being expressed by the electric field. Greater magnitude is expressed by the presence of more lines (higher line density) 

4b. The electric potential is measured in Volts(V) and is uniform along  the same equipotential line. What is an equipotential line(gray)? It is a line drawn perpendicular(forms a right angle with) to the magnetic field lines(black) to show the changes in electric potential. One space where electric potential will always be the same because it will always be equal to 0 Volts is exactly in between a positive and negative charges of equal charge value I have pointed to this line with a purple arrow in my picture.

I really hope this makes sense to you and that my pictures help! :)

3 0
3 years ago
An equipoterntial surface that surrounds a + 3.0 pC point charge has a radius of 2.0 cm. What is the potential of this surface?​
mestny [16]

Answer:

Electric potential = 0.00054 V

Explanation:

We are given;

Charge; q = 3 pC = 3 × 10^(-12) C

Radius; r = 2 cm = 0.02 m

Formula for the electric potential of this surface will be;

V = kqr

Where;

K is a constant = 9 × 10^(9) N⋅m²/C².

Thus;

V = 9 × 10^(9) × 3 × 10^(-12) × 0.02

V = 0.00054 V

8 0
3 years ago
A box of mass 45 kg is at rest on a horizontal frictionless surface. A constant horizontal force F then acts on the box and acce
S_A_V [24]

Answer:

F = 64.0 N

the magnitude of the force is 64 N

Explanation:

Given;

Mass m = 45kg

time t = 7.5 s

Displacement d = 40 m

Force = mass × acceleration

F = ma ........1

From equation of motion;

d = vt + 0.5at^2

Since initial velocity v = 0 (initially at rest)

d = 0.5at^2

Making a the subject of formula;

a = d/(0.5t^2)

Substituting the given values;

a = 40/(0.5×7.5^2)

a = 1.42 m/s^2

From equation 1;

F = ma

Substituting the given values;

Force F = 45 kg × 1.42 m/s^2

F = 64.0 N

the magnitude of the force is 64 N

7 0
3 years ago
An object with a mass of 6.3 kg has a force of 7.1 newtons applied to it.
vlada-n [284]

Answer:

F=ma

7.1=6.3×m

7.1÷6.3=m

m=1.126 kg

6 0
3 years ago
Why is it that when a door is open you can go through it, but when it is closed you have to open it to go through it?
LekaFEV [45]

Answer: Because we can’t walk through walls and in this case, doors.

Explanation: no

3 0
2 years ago
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