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vladimir1956 [14]
3 years ago
14

Which equation represents a proportional relationship that has a constant of proportionality equal to 2 with the answers are y=x

+2, y=x/2, y=2x, and y=2?
Mathematics
2 answers:
barxatty [35]3 years ago
8 0
Y=2x bc 2 equals k and the equation for direct variation is y=kx
Answer: y=2c
cupoosta [38]3 years ago
3 0
We know that
A relationship between two variables, x, and y,<span> is proportional if it can be expressed in the form y/x=k or y=kx</span>
in this problem
k=2
then
y=2x

therefore

the answer is the option
y=2x
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Find the area of an isosceles triangle with perimeter of 40 feet and a base of 12 feet. Round to the nearest whole number.
Aleksandr [31]

Answer: 76 ft2

Step-by-step explanation:

Perimeter = 2 side length +base length

40 = 2s +12

Solving for s:

40-12 =2s

28 =2s

28/2=s

14ft =side

Since the line which bisects and isosceles triangles is at a right angle to the base we can use the Pythagorean Theorem to find the height (see attachment)  

c^2 = a^2 + b^2  

Where c is the hypotenuse of the triangle (in this case 14) and a and b are the other sides. (Base divided by 2 is one side, the other side is the height)

Replacing with the values given:  

14^2= 6^2 + x^2

196 = 36 + x^2

196-36 = x^2

160 = x^2

√160 = x

x = 12.64 (height)

Area of an isosceles triangle = 1/2 x base x height  

A = 1/2 x 12 x 12.64 = 76 ft2

5 0
3 years ago
If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
3 years ago
Which equation cab be used to solve for x in the triangle below ?
Elis [28]

Answer:

AA

Step-by-step explanation:

7 0
3 years ago
A 65-story office tower has a height of 910 feet. Write an expression to find the height of each story. Then, use the expression
gizmo_the_mogwai [7]
Assuming each story is the same height
910=65 stories put together
910=65 times (height of each story)
910=65h
divide both sides by 65
14=h
each story is 14 feet

the equation is 910=65h
4 0
3 years ago
Read 2 more answers
“Jessie has 2/3 of a bag of apples that she wants to divide equally among her 5 siblings. What fractional part of the bag
Nesterboy [21]

Answer:

2/15

Step-by-step explanation:

2/3*5

2/3*1/5=2/15

*=multipliy

6 0
3 years ago
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