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3 years ago

A 25 n object requires a 5.0 n to start moving over a horizontal surface. what is the coefficient of static friction?

Physics

2 answers:

Cerrena [4.2K]3 years ago

7 0

Answer:

0,2 would be the coefficient of friction.

Explanation:

Remember that the force necessary to move an object over a horizontal surface is the weight of the object multiplied by the coeficient of friction, an the formula is this:

$Friction= u*N$

Where u is the coefficient of static friction and N is the normal force, or in this case the weight of the object so if we solve for U the formula would be like this:

$u=\frac{Friction}{N}$

Now we just insert the data we know:

$u=\frac{Friction}{N}\\u=\frac{5N}{25N}\\ u=0,2$

So the coefficient of friction would be 0.2

olganol [36]3 years ago

3 0

Static friction is the friction that exists between two or more solids that are not moving with a relative speed. To calculate the static friction coefficient we use the formula Fs=us × n where Fs is the static friction , us is the coefficient of static friction and the n is the normal force.
thus the coefficient of static friction will be 5 N÷ 25 N = 0.2
Hence 0.2 is the coefficient of static friction

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Now applying Hooke's Law:

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