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geniusboy [140]
3 years ago
11

There are many interesting applications of our energy density model to the flow of blood in the human circulatory system. One in

teresting phenomenon is an aneurysm, a sudden abnormal enlargement of a section of an artery due to a weakening of the arterial wall. If the blood flow rate remains constant through the artery, how does the pressure in the enlarged section (the aneurysm) compare to the pressure in the rest of the artery? Neglect any affects of resistance to flow in your explanation.

Physics
2 answers:
IgorLugansk [536]3 years ago
7 0

Answer:

Pressure in enlarged portion is greater than remaining portion of artery.

Explanation:

The Bernoullis equation at front and back side of arterial wall is given by:

qaws [65]3 years ago
5 0

Answer:

Pressure increases due to enlargement

Explanation:

Energy density is just a fancy name for pressure

Pressure is same at the bottom of the cups (same level-Pascal's law)

thus, Air pressure 1 + h1d1g = Air pressure 2 + h2d1g

= Air pressure 3 + (h2-h1)d2g +h1d1g

from the first 2, we get that since h2>h1, AP2<AP1

from the next 2, we get that since d2<d1, AP3>AP2

from first and third, we get that AP1>AP3

thus, finally AP1>AP3>AP2

for fluids flowing in tubes (blood vessel in this case)

P+0.5dv^2 + gh is constant (also called the bernoulli equation

for the same blood vessel, the heights remain same i.e h1=h2

for same flow rate, inc in area decreases the speed at which the blood flows as vA must remain same

hence, P increases due to enlargement

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find the resultant in the x-direction , Rx and y-direction , Ry for F1 = 2.5n in the positive x-direction f2 = 1n in the negativ
Advocard [28]

The resultant in the x-direction:

Rx = F1 + F2 = 2.5 N - 1 N =  1.5 N .


The resultant in the y-direction:

Ry = F3 + F4 = 2 N - 3 N =  -1 N.

5 0
3 years ago
If the horse lifts a 50 kilogram mass a vertical distance of 3 meters in 2 seconds, what is the horse’s minimum power output?
yaroslaw [1]

Answer:

735watts

Explanation:

Power = Force*distance/time

Given

Force = mg = 50 * 9.8'

Force = 490N

distance = 3m

time = 2s

Substitute

Power = 490*3/2

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Power = 735Watts

Hence the minimum power output is 735watts

7 0
3 years ago
Time period of a simple pendulum is measured at Karachi. What change will occur in the time period, if it is measured on mount e
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5 0
3 years ago
Difference between weightlessness in space and weightlessness in earth​
nadya68 [22]
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8 0
3 years ago
A 2430 pound roller coaster starts from rest and is launched such that it crests a 105 ft high hill with a speed of 59 mph. The
Rudik [331]

Answer:

Explanation:

Given

Weight of roller coaster is W=2430\ pound

mass of roller coaster m=\frac{W}{g}=\frac{2430}{32.2}=75.45

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drag force f_d=85\ pounds

velocity at top v=59 mph\approx 86.53\ ft/s

Suppose E is the initial energy

Conserving Energy at bottom and top

E=\frac{1}{2}mv^2+mgh+f_d\cdot d

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E=2.9\times 10^5\ foot-pound

5 0
3 years ago
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