Answer:
The answer to the question is;
The plate be left in the furnace for 905.69 seconds.
Explanation:
To solve the question, we have to check the Bi number as follows
Bi = 
As the Bi number is > 0.1 we have to account for the variation of temperature with location in the mass.
We perform nonlumped analysis
The relation for heat transfer given by
Y =
=
= 0.3968 = C₁ exp (ζ₁² F₀)
where
C₁ and ζ₁ are coefficients of a series solution
We therefore look for the values of C₁ and ζ₁ from Bi tables to be
ζ₁ = 0.4801 +(0.26-0.25) (0.5218-0.4801)/(0.3-0.25) ≈ 0.4884 and
C₁ = 0.4801 +(0.26-0.25) (1.0450 - 1.0382)/(0.3-0.25) ≈ 1.03956 and
This gives the relation
0.3968 = 1.03956 exp (ζ₁² F₀)
or ζ₁²
where
α = Thermal diffusivity of solid = k/(ρ·c
) =
= 1.1146×10⁻⁵
c
= Specific heat capacity of solid at constant pressure = 550 J/kg·K
ρ = Density of the solid = 7830 kg/m³
=㏑
= -0.9631 from where we have
t =
= 905 seconds.