Answer:
27.7 KJ
Explanation:
Q= mC dT
m= 1900 g+0.580 g= 1900.58 g
Q= (1900.58 g * 3.21 KJ/ gK* 4.542 K)
Q=27710 J= 27.7 KJ
To determine the pH of a weak base, we use the equation:
pH = 14 + 0.5 log Kb
Therefore,
pH = 14 + 0.5 log 3.25
pH = 14.26
A weak base is a base which does not fully dissociates into ions when in solution. The solution would contain cations, anions and the compound itself. Hope this helps.
Answer:
16.8%
Explanation:
31% NaOH molar mass 40 gm
69% H2O molar mass 18 gm
1000 gm would be
310 gm NaOH or 310/40 = 7.75 moles
690 gm of H2O or 690/18 = 38.333 moles
7.75 / (7.75 + 38.333) = .168 mole fraction
Answer:
Hexose category and ketohexose category
Explanation:
The classification of the Carbohydrate tagatose by carbonyl group is that it is a monosaccharide and has a hexose structure hence it belongs to the Hexose category
Based on the number of carbon atoms the structure has a ketofunctionality hence it is classified under the ketohexose category
Attached below is the remaining part of the solution
Answer:
21.16 MPa
Explanation:
Partial pressure of oxygen = 5.62 MPa
Total gas pressure = 26.78 MPa
But
Total pressure of the gas= sum of partial pressures of all the constituent gases in the system.
This implies that;
Total pressure of the system = partial pressure of nitrogen + partial pressure of oxygen
Hence partial pressure of nitrogen=
Total pressure of the system - partial pressure of oxygen
Therefore;
Partial pressure of nitrogen= 26.78 - 5.62
Partial pressure of nitrogen = 21.16 MPa
