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jasenka [17]
3 years ago
9

Both the physical and chemical properites of a substance can change when a substance undergoes a chemical reaction. When a log i

s burned, a chemical reaction occurs. The log is transformed into ash, water vapor, and carbon dioxide. The log is flammable, or able to be burned, in its original form. Once the log is burned, however, the ashes that are produced are no longer flammable. The volume of the log also changes when it changes into ash and gas. Volume is a _______ property. Flammability is a _______ property. A. chemical; physical B. physical; physical C. physical; chemical urgent TIME LIMIT 84PTS
Chemistry
2 answers:
ElenaW [278]3 years ago
6 0
Answer is option C...
e-lub [12.9K]3 years ago
3 0

The answer to your question is C. Physical; Chemical

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Tentacles with stinging cells, 2 body layers (ectoderm & endoderm), radially symmetric
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3 years ago
NH₄NO₃ → N₂O + 2H₂O When 45.70 g of NH₄NO₃ decomposes, what mass of each product is formed?
Anna007 [38]

Answer: 25.13 g of N_2O  and 20.56 g of H_2O will be produced from 45.70 g of NH_4NO_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} NH_4NO_3=\frac{45.70g}{80.04g/mol}=0.571moles

The balanced chemical equation is:

NH_4NO_3\rightarrow N_2O+2H_2O  

According to stoichiometry :

1 mole of NH_4NO_3 produce = 1 mole of N_2O

Thus 0.571 moles of NH_4NO_3 will require=\frac{1}{1}\times 0.571=0.571moles  of N_2O  

Mass of N_2O=moles\times {\text {Molar mass}}=0.571moles\times 44.01g/mol=25.13g

1 mole of NH_4NO_3 produce = 2 moles of H_2O

Thus 0.571 moles of NH_4NO_3 will require=\frac{2}{1}\times 0.571=1.142moles  of H_2O  

Mass of H_2O=moles\times {\text {Molar mass}}=1.142moles\times 18g/mol=20.56g

Thus 25.13 g of N_2O  and 20.56 g of H_2O will be produced from 45.70 g of NH_4NO_3

5 0
3 years ago
How many grams of barium sulfate, baso4, are produced if 25.34 ml of 0.113 m bacl2 completely react given the reaction: bacl2 +
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Answer is: mass of barium sulfate is 0.668 grams.
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V(</span>BaCl₂) = 25.34 mL ÷ 1000 mL/L = 0.02534 L.
c(BaCl₂) = 0.113 mol/L.
n(BaCl₂) = V(BaCl₂) · c(BaCl₂).
n(BaCl₂) = 0.02534 L · 0.113 mol/L.
n(BaCl₂) = 0.00286 mol.
From chemical reaction: n(BaCl₂) : n(BaSO₄) = 1 : 1.
n(BaSO₄) = 0.00286 mol.
m(BaSO₄) = n(BaSO₄) · M(BaSO₄).
m(BaSO₄) = 0.00286 mol · 233.4 g/mol.
m(BaSO₄) = 0.668 g.
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3 years ago
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Write the empirical formula for at least four ionic compounds ca2+.v5+,f-,s2
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Using these Elements. Here would be the 4 ionic compounds.

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List at least one reason for not touching the magnesium metal with bare hands. 3. list two reasons for using crucible tongs to h
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Crucible tongs are mandatory to handle hot crucibles to avoid skin burns and accidents during experimental procedures. Crucible tongs work with the crucible; their shape was designed to firmly hold it to avoid spills.

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4 years ago
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