Answer:
1455.6
Explanation: you first convert 2250ml to l by dividing by 1000 so you get 2.25l then you use Boyles law which is p1v1=p2v2 then insert values
35.75*100=p2*2.25 then divide both sides by 2.25 then you get 1455.6
If you cut the cube and keep all the pieces you are causing only physical change
MgF2 is <span>Magnesium fluoride
hope this helps!</span>
Sucrose and other simple sugars may dissolve in water because they are polar molecules with an unequal charge distribution. Water is also quite polar, capable of forming weak, temporary connections with other polar compounds.
Salt dissolves into ions, with Na being positively charged and CL being negatively charged. Because water is highly polar (parts of the molecule are negatively charged while others are positively charged), the sodium ions are surrounded by water molecules, with the negatively charged component of the water molecules surrounding the NA ion. The Cl ion experiences the inverse effect.
<h3>
How does salt dissolve in water compared to sugar?</h3>
A solution's solute and solvent are two different types of substances that can dissolve one another. Different solvents have different levels of solubility for different solutes. For instance, sugar is far more soluble in water than salt. Even sugar, though, has a limit on how much may dissolve.
learn more about solubility refer:
brainly.com/question/23946616
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Answer:
[H₂] = 1.61x10⁻³ M
Explanation:
2H₂S(g) ⇋ 2H₂(g) + S₂(g)
Kc = 9.30x10⁻⁸ = ![\frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH_%7B2%7D%5D%5E2%5BS_%7B2%7D%5D%7D%7B%5BH_%7B2%7DS%5D%5E2%7D)
First we <u>calculate the initial concentration</u>:
0.45 molH₂S / 3.0L = 0.15 M
The concentrations at equilibrium would be:
[H₂S] = 0.15 - 2x
[H₂] = 2x
[S₂] = x
We <u>put the data in the Kc expression and solve for x</u>:
We make a simplification because x<<< 0.0225:
x = 8.058x10⁻⁴
[H₂] = 2*x = 1.61x10⁻³ M
