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PSYCHO15rus [73]
3 years ago
8

At a particular temperature and [A]0 = 2.00 x 10-2 Molar, concentration versus time data were collected for this reaction and a

plot of ln[A]t versus time resulted in a straight line with a slope value of -2.97 x 10-2 min-1.
What is the half-life of this reaction?
Chemistry
1 answer:
madreJ [45]3 years ago
4 0
<h2>Answer:kllk<em>klkkkk</em></h2>

Explanation:

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A 8.2 L sample of gas has a pressure of 0.8 atm at a temperature of 259 K. If the temperature increases to 301 K, causing the vo
Rina8888 [55]

The answer is 0.7 atm


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3 years ago
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What hydrocarbons burn completely in an excess of oxygen, the products are
Sindrei [870]
The right answer for the question that is being asked and shown above is that: "C) carbon monoxide and carbon dioxide" hydrocarbons burn completely in an excess of oxygen, the products are <span>C) carbon monoxide and carbon dioxide</span>
3 0
3 years ago
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Jane has a weight of 500 N. The area of her two feet is 250 cm2. The pressure when she is standing is Pressure = 500/250 = 2 N/c
weeeeeb [17]

Explanation:

pressure=force/area

pressure=500/2

pressure=250N/cm²

8 0
3 years ago
A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *
elena-14-01-66 [18.8K]

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (kPa)
  2. P2 = final pressure (kPa)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

Learn more about Boyle's law calculations at: brainly.com/question/1437490?referrer=searchResults

3 0
2 years ago
How many grams of CO2 evolved from a 1.205g sample that is 36% MgCO3 and 44% K2CO3 by mass?
emmasim [6.3K]

Mass of CO₂ evolved : 0.108 g

<h3>Further explanation</h3>

Given

1.205g sample, 36% MgCO3 and 44% K2CO3

Required

mass of CO2

Solution

  • mass of MgCO₃ :

0.36 x 1.205 g=0.4338 g

mass C in MgCO₃(MW MgCO₃=84 g/mol,  Ar C = 12/gmol)

= (12/84) x 0.4338

= 0.062 g

  • mass of K₂CO₃ :

0.44 x 1.205 g = 0.5302 g

Mass C in K₂CO₃(MW=138 g/mol) :

= (12/138) x 0.5302

= 0.046 g

Total mass Of CO₂ :

= 0.062 + 0.046

= 0.108 g

7 0
3 years ago
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