If you observe an object in the universe that is roughly 8 megaparsecs in size, what is the object most likely to be?

mariarad [96]

Answer:

$g_{moon}=1.67 [m/s^{2} ]$

Explanation:

The weight of some mass is defined as the product of mass by gravitational acceleration. In this way using the following formula we can find the weight.

$w =m*g\\$

where:

w = weight [N]

m = mass = 0.06 [kg]

g = gravity acceleration = 10 [N/kg]

Therefore:

$w=0.06*10\\w=0.6[N]$

By Hooke's law we know that the force in a spring can be calculated by means of the following expression.

$F=W\\F = k*x$

where:

k = spring constant [N/m]

x = deformed distance = 6 [cm] = 0.06 [m]

We can find the spring constant.

$k= F/x\\k=0.6/0.06\\k=10 [N/m]$

Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.

$F_{moon}=k*0.01\\F = 10*0.01\\F=0.1[N]$

Since this force is equal to the weight, we can now determine the gravitational acceleration.

$F=m*g_{moon}\\g=F/m\\g = 0.1/0.06\\g_{moon} = 1.67[m/s^{2} ]$

6 0

3 years ago

A dragster completed a 402.3-(0.2500-mi) run in 5.023s. If the car had a constant acceleration, what was its acceleration and fi

Ray Of Light [21]

Answer:

v = 80.092 m/s

a = 15.945 m/s²

Explanation:

Given,

The distance completed by the dragster, d = 402.3 m

The time taken by the dragster to complete that distance is, t = 5.023 s

The initial velocity of the dragster, u = 0

The final velocity of the dragster, v = ?

The acceleration of the dragster, a = ?

The velocity of the body is given by the formula

v = d/t m/s

Substituting the above values inn the equation

v = 402.3 m / 5.023 s

= 80.092 m/s

So, the velocity of the dragster is, v = 80.092 m/s

The acceleration of the body is given by the formula

a = (v - u)/t m/s²

Substituting the above values in the equation

= (80.092 - 0) / 5.023

= 15.945 m/s²

Hence, the acceleration of the dragster is, a = 15.945 m/s²

6 0

3 years ago

What kind of physics is used to describe the interaction of matter and energy from the beginning of the cosmic singularity to th

lisov135 [29]

Cosmology physics is used to describe the interaction of matter and energy from the beginning of the cosmic singularity to the Planck time.

Astronomy's field of cosmology examines the beginnings and development of the universe, from the Big Bang through the present and into the future. The current cosmology model for the development of the universe is the Big Bang theory, which relies on the validity of general relativity. There is a singularity there as well.

According to the Big Bang theory, the cosmos was once compressed into an infinitely small point 13.77 billion years ago. Prior to $10^{-43}$ seconds after the Big Bang, during the Planck Era, gravity, nuclear strong, nuclear weak, and electromagnetic forces are thought to have been merged into a single "super" force.

Learn more about big bang theory here;

brainly.com/question/18297161

#SPJ4

3 0

2 years ago

How can one object affect the motion of another without touching it?

stealth61 [152]

By non-contact forces (e.g. gravitational force and electric force)

Explanation:

In order for an object to exert a force on another object, the two object can also be not touching each other. In fact, there exist some non-contact forces in nature.

Concerning macroscopic objects, the two main non-contact forces acting between objects are:

- The gravitational force: this force is exerted between every object that has mass. It is always attractive, and its magnitude is given by

$F=G\frac{m_1 m_2}{r^2}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

- The electric force: this force is exerted between objects that have electric charge. It can be either attractive or repulsive, and its magnitude is given by

$F=k\frac{q_1 q_2}{r^2}$