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ASHA 777 [7]
1 year ago
11

At what angle should the roadway on a curve with a 45 m radius be banked to allow cars to negotiate the curve at 12 m/s even if

the roadway is icy (and the frictional force is zero)?.
Physics
1 answer:
nordsb [41]1 year ago
8 0

At an angle of  18.26 °  the roadway on a curve with a 45 m radius be banked to allow cars to negotiate the curve at 12 m/s even if the roadway is icy

angle of banking of the car going round the curve = tan (theta) = v^{2}  / rg

v = speed

r = radius

g = acceleration due to gravity

substituting the values

tan (theta)  = 12^{2} / 45 * 9.8  = 0.33  

theta = tan^{-1} (0.33)

         = 18.26 °

At an angle of  18.26 °  the roadway on a curve with a 45 m radius be banked to allow cars to negotiate the curve at 12 m/s even if the roadway is icy .

To learn more about acceleration due to gravity here :

brainly.com/question/13860566

#SPJ4

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the value of force, F=4.0N

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7 0
2 years ago
A rocket weighs 9800N (opposing force) what is it mass? What netforce moves the rocket? What applied force gives it a vertical a
Slav-nsk [51]

For the first part of this question, consider that "weight" can be described as mass x acceleration of gravity. Weight is expressed in Newtons. To solve for mass in this case, simply divide 9800N by 9.8m/s^2 (Earth's gravitational acceleration). This will give you a mass of 1000 kg. This mass is moved due to the net force supplied by the normal force from the rocket "pushing" off of Earth.

For the second part, we will use the equation F = ma, which is Newton's second law. For this, we know the m, or mass, is 1000 kg. Also, we know the a, or acceleration, will be 4 m/s^2. To solve for force, we will multiply both of these values. This gives a force of 4000 N. I hope this clears things up!

6 0
3 years ago
4. What is the magnitude and direction of the gravitational force that acts on a man
Cloud [144]

The gravitational force acting on the man is 800 N towards the Earth's centre

Explanation:

The weight of an object on the Earth is exactly the gravitational force exerted by the Earth on the object.

The gravitational force exerted by the Earth on an object located at the Earth's surface is given by:

F=G\frac{Mm}{R^2}

where

G is the gravitational constant

M is the Earth's mass

m is the mass of the object

R is the radius of the Earth

And the direction of the force is towards the Earth's centre.

Since G, M and R are constant, they are grouped into a single constant called g, acceleration of gravity:

g=\frac{GM}{R^2}

therefore the gravitational force can be rewritten as

F=mg

And this is the usual equation that we use to calculate the weight of an object.

Therefore, weight and gravitational force acting on an object on Earth are the same thing: so, the gravitational force acting on the man is equal to his weight, 800 N, and it acts towards the Earth's center.

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There are two tuning forks struck at the same time. One tuning fork is tuned to a frequency note of 500 Hz. The other is tuned t
fomenos

Answer: 26 beats in 2 seconds

Explanation:

The number of beats per second = frequency of tuning fork 1 - frequency of tuning fork 2.

Given :

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Thus,

Beats per second = 500 - 487

= 13 beats per second

Therefore in two(2) seconds, you will have 2 x 13 = 26 seconds.

6 0
3 years ago
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