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Anna71 [15]
3 years ago
8

2. Why should a magnesium ribbon be cleaned before burning in air ?​

Chemistry
1 answer:
Nesterboy [21]3 years ago
8 0
To remove magnesium oxide layer from the ribbon which may prevent or slow down the burning of magnesium ribbon.
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For each of the scenarios, identify the order with respect to the reactant, A. A⟶products The half‑life of A increases as the in
nirvana33 [79]

Answer:

Answers are in the explanation.

Explanation:

  • The half‑life of A increases as the initial concentration of A decreases. order: <em>2. </em>In the half-life of second-order reactions, the half-life is inversely proportional to initial concentration.
  • A three‑fold increase in the initial concentration of A leads to a nine‑fold increase in the initial rate. order: <em>2. </em>The rate law of second-order is: rate = k[A]²
  • A three‑fold increase in the initial concentration of A leads to a 1.73‑fold increase in the initial rate. order: <em>1/2. </em>The rate law for this reaction is: rate = k √[A]
  • The time required for [A] to decrease from [A]₀ to [A]₀/2 is equal to the time required for [A] to decrease from [A]₀/2 to [A]₀/4. order: <em>1. </em>The concentration-time equation for first-order reaction is: ln[A] = ln[A]₀ - kt. That means the [A] decreasing logarithmically.
  • The rate of decrease of [A] is a constant. order: <em>0. </em>The rate law is: rate = k -<em>where k is a constant-</em>
4 0
3 years ago
How many grams of iron (3)sulfide are produced when 131 grams of iron react with excess sulfur?
Tomtit [17]

<u>We want the molar mass (gfm) of Fe and FeS.</u>

Fe = 55.8 g/mol and FeS = 87.8 g/mol (55.8 +32.0).

<u>Explanation:</u>  

We want  ratio between Fe:FeS 8:8. This comes from the coefficients of the equal chemical equation.

Now we set up conversion factors following the roadmap from above.

Unit we want in the numerator, unit to cancel in the denominator.

Multiply the numerators, and divide the denominators.

(131.0)gFe \times 1molFe/(55.8)gFe \times 8molFeS/8molFe \times 87.8gFes/1molFes

243.82 g \ of Fe_2S_3

The outcome is 243.82 g of ferrous sulphite

By the above given formula we can find any amount of Fes produced by any amount of  ferrous react with sulphite.

4 0
4 years ago
Read 2 more answers
Consider the reaction of glucose with oxygen: C6H12O6(s) + 6O2(g) Right arrow. 6CO2(g) + 6H2O(l)
lidiya [134]

Answer:

Subtract the sum of the heats of formation of the reactants from that of the products to determine delta H: delta H = –110.53 kJ/mol – (–285.83 kJ/mol) = 175.3 kJ.

Explanation:

Step 1: Set Up the Equation. Arrange your given ΔHf and ΔH values according to the following equation: ΔH = ΔHf (products) - ΔHf (reactants). ...

Step 2: Solve the Equation. Solve your equation for ΔHf. ...

Step 3: Validate the Sign. Adjust your ΔHf value's sign depending on whether it is for a product or a reactant.

3 0
3 years ago
How many significant figures are in 0.00375
Galina-37 [17]

Answer:

There are 3 significant figures

3 0
3 years ago
Atom can<br> The ground state electronic configuration of<br> be represented by
Elan Coil [88]

Answer:

Ground state electronic configuration of nitrogen atom can be represented by 1, 4 only. All the unpaired electrons have spins aligned in the same direction only.

Explanation:

7 0
3 years ago
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