0.0179 ohms for copper.
0.0184 ohms for annealed copper
Ď = R (A/l) where
Ď = electrical resistivity
R = electrical resistance of a uniform specimen
A = cross sectional area
l = length
Solve for R by multiplying both sides by l/A
R = Ď(l/A)
The cross section of the wire is pi * 1^2 mm = 3.14159 square mm = 3.14159e-6 square meters.
The length is 3 meters. So l/A = 3/3.14159e-6 = 9.5493e5
Ď for copper is 1.68e-8 so 1.68e-8 * 9.5493e5 = 1.60e-2 ohms at 20 C
But copper has a temperature coefficient (α) of 0.00386 per degree C.
So the resistance value needs to be adjusted based upon how far from 20 C the temperature is.
50 - 20 = 30 C
So 0.00386 * 30 = 0.1158 meaning that the actual resistance at 50 C will be 11.58% higher.
So 1.1158 * 0.016 = 0.0179 ohms.
If you're using annealed copper, the values for Ď and the temperature coefficient change.
Ď = 1.72e-8
α = 0.00393
Doing the math, you get
1.72e-8 * 9.5493e5 * (1 + 30 * 0.00393) = 0.0184 ohms
Answer:
9.5 m/s
Explanation:
Distance, S = 150m
Acceleration, a = 0.3 m/s^2
Initial velocity, u = 0 m/s
Final velocity, v
Use kinematics equation
v^2 - u^2 = 2aS
v^2 - 0 = 2*0.3*150 = 90
v = sqrt(90) = 9.49 m/s
If a cell is placed in a hypertonic solution, water will leave the cell, and the cell will shrink. In an isotonic environment, there is no net water movement, so there is no change in the size of the cell. When a cell is placed in a hypotonic environment, water will enter the cell, and the cell will swell.
Answer:
It's perimeter
Explanation:
That's what it said when I looked it up so hopefully that's correct.
