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liberstina [14]
2 years ago
14

Calculate the mechanical advantage if a machine allows you to move a 60 newton rock by only exerting 15 newtons of force.

Physics
2 answers:
murzikaleks [220]2 years ago
6 0

Answer:

4 Newtons

Explanation:

  • I think it's 4 because mechanical advantage = output force/input force
  • So, it would be 60/15, which is 4 newtons
allochka39001 [22]2 years ago
5 0

Answer:

4

Explanation:

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¿Cuál es la masa aproximada del aire en una habitación de 5.6 m * 3.8 m * 2.8 m?
Nady [450]
It would be 3.15 in meters
8 0
3 years ago
A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball le
dangina [55]

Momentum should be conserved. The momentum of both objects must balance with their initial and final momentum.

Let m1 and v1 be the mass and velocity of the bowling ball

And m2 and v2 be the mass and velocity of the bowling pin

(m1v1)i + (m2v2)i = (m1v1)f + (m2v2)f

30 kg m/s + (1.5 kg)(0 m/s) = 13kg m/s + 1.5v2f

V2f = 11.33 m/s

<span>So the momentum = 1.5 kg(11.33 m/s) = 17 kg m/s</span>

8 0
2 years ago
5. A cart with one fan on It blowing to the left and carrying one block produces the x vs t graph shown If this car were carryin
kumpel [21]

Answer:

Graph C

Explanation:

With the same force and more mass, the position in time will still be parabolic

i.e.  x = ½at², but the rate of acceleration will be lower so the position curve will be broader.

5 0
3 years ago
Select the situation for which the torque is the smallest.
alina1380 [7]

Answer:

e. The torque is the same for all cases.

Explanation:

The formula for torque is:

τ = Fr

where,

τ = Torque

F = Force = Weight (in this case) = mg

r = perpendicular distance between force an axis of rotation

Therefore,

τ = mgr

a)

Here,

m = 200 kg

r = 2.5 m

Therefore,

τ = (200 kg)(9.8 m/s²)(2.5 m)

<u>τ = 4900 N.m</u>

<u></u>

b)

Here,

m = 20 kg

r = 25 m

Therefore,

τ = (20 kg)(9.8 m/s²)(25 m)

<u>τ = 4900 N.m</u>

<u></u>

c)

Here,

m = 8 kg

r = 62.5 m

Therefore,

τ = (8 kg)(9.8 m/s²)(62.5 m)

<u>τ = 4900 N.m</u>

<u></u>

Hence, the correct answer will be:

<u>e. The torque is the same for all cases.</u>

6 0
3 years ago
A current of 0.2 A flows through a conductor for 5minutes. How much charge would have passed through the conductor?​
Montano1993 [528]

As we know,

electric \:  \: current =  \dfrac{charge}{time}

so, let's solve for charge (q) :

time = 5 minutes = 5 × 60 seconds = 300 seconds.

  • 0.2 =  \dfrac{q}{300}

  • q = 300 \times 0.2

  • q = 60

hence, the charge = 60 coulombs (C)

4 0
2 years ago
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