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2 years ago

What happens when air from the balloon has exited the balloon? How will motion change?

Physics

1 answer:

tiny-mole [99]2 years ago

6 0

Answer:

When you release the opening of the balloon, gas quickly escapes to equalize the pressure inside with the air pressure outside of the balloon. The escaping air exerts a force on the balloon itself. ... That opposing force—called thrust, in this case—propels the rocket forward.

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SCIENCE

wolverine [178]

Answer:

A. It is made of tissues that can conduct electricity, a required function in a system.

Explanation:

The nervous system helps all the parts of the body to communicate with each other. It also reacts to changes both outside and inside the body. The nervous system uses both electrical and chemical means to send and receive messages.

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3 years ago

Read 2 more answers

A 200-Ω resistor is connected in series with a 10-µF capacitor and a 60-Hz, 120-V (rms) line voltage. If electrical energy costs

Vika [28.1K]

Answer:

Cost to leave this circuit connected for 24 hours is $ 3.12.

Explanation:

We know that,

$\mathrm{X}_{\mathrm{c}}=\frac{1}{2 \pi \mathrm{fc}}$

f = frequency (60 Hz)

c= capacitor (10 µF = $10^-6$ )

$\mathrm{X}_{\mathrm{c}}=\text { Capacitive reactance }$

Substitute the given values

$\mathrm{X}_{\mathrm{c}}=\frac{1}{2 \times 3.14 \times 10 \times 10^{-6} \times 60}$

$\mathrm{X}_{\mathrm{c}}=\frac{1}{3.768 \times 10^{-3}}$

$\mathrm{x}_{\mathrm{c}}=265.39 \Omega$

Given that, R = 200 Ω

$X^{2}=R^{2}+X c^{2}$

$X^{2}=200^{2}+265.39^{2}$

$X^{2}=40000+70431.85$

$X^{2}=110431.825$

$x=\sqrt{110431.825}$

X = 332.31 Ω

$\text { Current }(I)=\frac{V}{R}$

$\text { Current }(I)=\frac{120}{332.31}$

Current (I) = 0.361 amps

“Real power” is only consumed in the resistor,

$\mathrm{I}^{2} \mathrm{R}=0.361^{2} \times 200$

$\mathrm{I}^{2} \mathrm{R}=0.1303 \times 200$

$\mathrm{I}^{2} \mathrm{R}=26.06 \mathrm{Watts} \sim 26 \mathrm{watts}$

In one hour 26 watt hours are used.

Energy used in 54 hours = 26 × 24 = 624 watt hours

E = 0.624 kilowatt hours

Cost = (5)(0.624) = 3.12

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2 years ago

You have a length of tubing that is closed at one end. You cut the tubing into two pieces of unequal length, giving you a tube o

umka21 [38]

Answer:

The funda mental frequency of the original tube is 182Hz.

Explanation:

See the attachment for the calculation steps.

In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.

For closed tubes

f = nv/4L (n = 1, 3, 5,...n)

f = nv/2L (n = 1, 2, 3,...n)

The details of calculation can be found below in the attachment.

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3 years ago

The lowest-pitch tone to resonate in a pipe of length L that is closed at one end and open at the other end is 200 Hz. Which one

ozzi

Answer:

e. 400 Hz

Explanation:

In closed organ pipe, only odd harmonics of fundamental note is possible .

The fundamental frequency is 200 Hz . Then other overtones will be having following frequencies .

200 x 3 , 200 x 5 , 200 x 7 , 200 x 9 etc

600 Hz , 1000 Hz , 1400 Hz , 1800 Hz .

Frequency not possible is 400 Hz .

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3 years ago

PLZ HELP!!!!!!! My favorite playground equipment is the swings. In 1-3 sentences explain a pattern of motion that u predict u'll

In-s [12.5K]

My favorite playground equipment is the swings.

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3 years ago

What happens when air from the balloon has exited the balloon? How will motion change?​

What happens when air from the balloon has exited the balloon? How will motion change?