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yaroslaw [1]
4 years ago
13

What happens to the coefficient of friction when the weight is increased? Why is this?

Physics
2 answers:
sp2606 [1]4 years ago
8 0

Answer:

The coefficient of friction does not change.

Explanation:

The reason for this is that the coefficient friction depends only on one variable, which is the nature of the surfaces in contact. Therefore, weight has no effect whatsoever on the coefficient of friction. hence, No change occurs in the coefficient of friction if the weight is changed.

hope it helped ya.

Crazy boy [7]4 years ago
6 0

Answer:

Usually the coefficient of friction remains unchanged

Explanation:

The coefficient of friction should in the majority of cases, remain constant no matter what your normal force is. When you apply a greater normal force, the frictional force increases, and your coefficient of friction stays the same. Here's another way to think about it: because the force of friction is equal to the normal force times the coefficient of friction, friction is increased when normal force is increased.

Plus, the coefficient of friction is a property of the materials being "rubbed", and this property usually does not depend on the normal force.

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100 joule of kinetic energy
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What is physics and biology​
lorasvet [3.4K]

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Explanation:

8 0
3 years ago
A flat, circular loop has 18 turns. The radius of the loop is 15.0 cm and the current through the wire is 0.51 A. Determine the
Ostrovityanka [42]

Answer:

The magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.

Explanation:

Given;

number of turns of the flat circular loop, N = 18 turns

radius of the loop, R = 15.0 cm = 0.15 m

current through the wire, I = 0.51 A

The magnetic field through the center of the loop is given by;

B = \frac{N\mu_o I}{2R}

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

B = \frac{N\mu_o I}{2R} \\\\B = \frac{18*4\pi*10^{-7} *0.51}{2*0.15} \\\\B = 3.846 *10^{-5} \ T

Therefore, the magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.

6 0
4 years ago
Consider a box weight 2700 newtons resting on the ground. If the area of the box touching the ground is 1.5 square meters, what
Neko [114]

Answer:

The answer to your question is 1800 Pa

Explanation:

Data

Weight = 2700 N

Area = 1.5 m²

Pressure = ?

Formula

Pressure = Force / Area

The Pressure is defined as the force exerted per unit area.

-Substitution

 Pressure = 2700 / 1.5

-Result

 Pressure = 1800 Pa

The units of pressure are Pascals (Pa)

6 0
3 years ago
What is the angle of refraction?<br> 15 degrees<br> 30 degrees<br> 74 degrees
Sophie [7]

Answer:

74 degrees

Explanation:

***************

8 0
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