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Karolina [17]
3 years ago
12

Marco is conducting an experiment. He knows the wave that he is working with has a wavelength of 32. 4 cm. If he measures the fr

equency as 3 hertz, which statement about the wave is accurate? The wave has traveled 32. 4 cm in 3 seconds. The wave has traveled 32. 4 cm in 9 seconds. The wave has traveled 97. 2 cm in 3 seconds. The wave has traveled 97. 2 cm in 1 second.
Physics
1 answer:
sineoko [7]3 years ago
7 0

The true statement about the wave is that, the wave has traveled 97. 2 cm in 1 second.

In Physics, we define a wave as a disturbance along a medium that transfers energy. The wavelength of a wave is the distance covered by the wave while the frequency of the wave is the number of cycles of the wave completed per second.

The period of the wave is the inverse of the frequency of the wave. It is defined as the time taken for the wave to complete a cycle and it is measured in seconds.

The wave formula is given as;

v = λf

v = velocity of the wave (distance traveled by the wave in one second)

λ = wavelength of the wave

f = frequency of the wave

So;

λ = 32.4 cm

f =  3 hertz

v = 32.4 cm × 3 hertz

v = 97. 2 cms-1

Hence, the true statement about the wave is that, the wave has traveled 97. 2 cm in 1 second.

Learn more: brainly.com/question/14588679

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Hi!

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Displacement = 1/2 (10 * 8.5^2) + 0

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3 years ago
A certain helium-neon laser pointer, emitting light with a wavelength of 632 nm, has a beam with an intensity of 825 W/m2 and a
BabaBlast [244]

Answer:

N = 1.62 \times 10^{15}

Explanation:

Energy of each photon is given as

E = \frac{hc}{\lambda}

here we will have

\lambda = 632 nm

now we will have

E = \frac{(6.626\times 10^{-34})(3 \times 10^8)}{632 \times 10^{-9}}

E = 3.14 \times 10^{-19} J

now let say there is N number of photons per second

so power due to photons is

P = N(3.14 \times 10^{-19})

now intensity is given as power received per unit area

so we have

I = \frac{P}{A}

825 = \frac{N(3.14 \times 10^{-19})}{\pi (1.40 \times 10^{-3})^2}

825 = N(5.11 \times 10^{-14})

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5 0
3 years ago
Where is the best place to put pfds while you are out on your boat?
Alexeev081 [22]
The best place to put PFDs while you are out on your boat is at the top deck of your boat. PFDs must be placed at an area where it is easily accessible, especially in times of accidents, without any unnecessary gear or objects covering the PFDs, but it is best to wear a life jacket during the whole duration of the boat trip.
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3 years ago
How is the direction of light changed when it travels from an optically denser medium to an optically rarer medium????? please a
ANTONII [103]

Answer:

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Explanation:

We can solve the problem by using Snell's law:

n_1 sin \theta_1 = n_2 sin \theta_2

where:

n_1 is the index of refraction of the first medium

n_2 is the index of refraction of the second medium

\theta_1 is the angle of incidence (angle between the incoming ray and the normal to the interface)

\theta_2 is the angle of refraction (angle between the outcoming ray and the normal to the interface)

We can rearrange the equation as

sin \theta_2 = \frac{n_1}{n_2}sin \theta_1

In this problem, light travels from an optically denser medium to an optically rarer medium, so

n_1 > n_2

Therefore, the term \frac{n_1}{n_2} is greater than 1, so

sin \theta_2 > sin \theta_1\\\rightarrow \theta_2 > \theta_1

which means that the angle of refraction is greater than the angle of incidence, and so the light will bend away from the normal.

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3 years ago
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erastovalidia [21]

Answer:

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3 years ago
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