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During the new moon phase, why is the Moon not visible in the sky?

Gennadij [26K]

Answer:

Explanation:

The moon gets the light from the sun. When the moon lies between the sun and the earth, only the back portion of the moon gets the light from the sun. So the side facing the sun does not get any light and appears to be dark or does not appear at all.

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3 0

3 years ago

A piece of Nichrome wire has a radius of 6.5 104 m. It is used in a laboratory to make a heater that uses 4.00 102 W of power wh

Delvig [45]

Answer:

$L=4.8*10^{17}m$

Explanation:

Given data

Power P=4.00×10²W

Radius r=6.5×10⁴m

Voltage V=120V

To find

Length of wire L

Solution

We know that resistance of wire can be obtained from

$P=\frac{V_{2}}{R}\\ R=\frac{V_{2}}{P}$

We also know that R=pL/A solving the length noting that A=πr²

and using p=100×10⁻⁸Ω.m we find that

So

$L=\frac{RA}{p}\\ L=\frac{\frac{(V^{2})}{P}(\pi r^{2}) }{p} \\L=\frac{V^{2}(\pi r^{2})}{pP}\\ L=\frac{(120V)^{2}\pi (6.5*10^{4} m)^{2} }{100*10^{-8}(4.00*10^{2} W) }\\ L=4.8*10^{17}m$

6 0

3 years ago

Suppose that in a lightning flash the potential difference between a cloud and the ground is 1.3×109 V and the quantity of charg

Georgia [21]

Answer:

A) ΔU = 3.9 × 10^(10) J

B) v = 8420.75 m/s

Explanation:

We are given;

Potential Difference; V = 1.3 × 10^(9) V

Charge; Q = 30 C

A) Formula for change in energy of transferred charge is given as;

ΔU = QV

Plugging in the relevant values gives;

ΔU = 30 × 1.3 × 10^(9)

ΔU = 3.9 × 10^(10) J

B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.

This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.

Thus;

P.E = K.E

ΔU = ½mv²

Where v is final velocity.

Plugging in the relevant values;

3.9 × 10^(10) = ½ × 1100 × v²

v² = [7.8 × 10^(8)]/11

v² = 70909090.9090909

v = √70909090.9090909

v = 8420.75 m/s

4 0

3 years ago

What is the approximate de Broglie wavelength of a tennis ball with a mass of 70 g and a velocity of 10 m/s

dybincka [34]

The approximate de Broglie wavelength of a tennis ball is 9.4×10^(-34) m.

What is the de Broglie wavelength:

It is the wavelength that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength.

A particle's de Broglie wavelength is usually inversely proportional to its force.

The formula of de Broglie wavelength:

λ = h / ( m*v )

here mass of a tennis ball is given

mass, m=70 g = 0.07 kg

ball is moving with velocity

v = 10 m/s

h is Plank constant,

h=6.63×10^(-34) Js

substituting the values in formula,

λ = 6.63×10^(-34) / ( 0.070*10)

λ = 9.4 ×10^(-34) m

Hence

The approximate de Broglie wavelength of a tennis ball is 9.4×10^(-34) m

Learn more about de Broglie wavelength here:

<u>brainly.com/question/17295250</u>

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3 0

2 years ago

In a longitudinal wave, the particles of matter in the medium vibrate by pushing together and moving apart. In a transverse wave

Lilit [14]

Answer:

C. The particles in longitudinal waves travel parallel to the direction of the wave, whereas the particles in transverse waves travel perpendicular to the direction of the wave.

Explanation:

Longitudinal waves are waves that propagates energy from their source by movement of particles in a direction parallel to the wave motion.

Transverse waves produce oscillations that are perpendicular to the direction of propagation.

Examples of longitudinal waves are sound waves, seismic p-waves
Examples of transverse waves are electromagnetic waves

A wave is a disturbance that transmits energy from one point to another.

8 0

3 years ago