Answer: 
Explanation:
Given
mass of wagon m=5 kg
elevation
Sin component of weight will oppose the applied force therefore we can write
I am pretty sure it is A Becoming warm
Since it’s moving and causing friction which makes it warm
Hope this helps
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Answer:
The work done by the child to reach the cat is, W = 3684.8 J
Explanation:
Given data,
The mass of the child, m = 40 kg
The height of the cat from the ground, h = 9.4 m
The force acting on the child due to gravitational force is,
F = mg
The minimum force required by the child to climb the tree against the gravitational force is,
F = mg
Hence, the work done by the child is,
W = F · h
= 40 x 9.8 x 9.4
= 3684.8 joules
Hence, the work done by the child to reach the cat is, W = 3684.8 J
Answer:
<em>a) 3344 N</em>
<em>b) 3344 N</em>
Explanation:
This is the complete question
1100 kg car pushes a 2200 kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 5000 N. Rolling friction can be neglected. A. What is the magnitude of the force of the car on the truck? Express your answer to two significant figures and include the appropriate units. B. What is the magnitude of the force of the truck on the car?
Mass of the car = 1100 kg
Mass of the truck = 2200 kg
Force exerted on the ground by the car = 5000 N
The total mass in the system = 1100 + 2200 = 3300 Kg
Total force in the system = 5000 N
Recall that the force in the system = mass x acceleration
therefore,
5000 = 3300 x a
Total acceleration in the system = 5000/3300 = 1.52 m/s^2
The force on the truck individually fro the car, will be the product of this acceleration and its mass
Force on the truck = 2200 x 1.52 = <em>3344 N</em>
b) Force on the car From the truck will be equal to this force but will act in the opposite direction.
Force on the car from the truck is <em>3344 N </em>
