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2 years ago

An actual measurement of a sample is 3.5 m. The measured

Chemistry

2 answers:

zhannawk [14.2K]2 years ago

6 0

Answer:

B. 29 percent

Explanation:

hope this helps

strojnjashka [21]2 years ago

5 0

Answer: b 29 percent

Explanation:

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Which statement is true for all minerals?

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A. because atoms create crystal structures to form different kind of materials

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2 years ago

Sulfuric acid (H2SO4) is a very strong diprotic acid. If 0.054 moles of sulfuric acid is mixed with water to make 667 milliliter

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3 years ago

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The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.

atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M

Explanation:

The photodissociation of ozone by UV light is given by:

O₃ + hν → O₂ + O (1)

The first-order reaction of the equation (1) is:

$rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t}$ (2)

where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration

We can get the following expression of the first-order integrated law of the reaction (1), by resolving the equation (2):

$[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt}$ (3)

where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration

We can calculate the initial ozone concentration using equation (3):

$[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M$

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!

3 0

3 years ago

A rigid cylinder with a movable piston contains a sample of hydrogen gas. At 330. K, this sample has a pressure of 150. kPa and

Marta_Voda [28]

Answer:

V₂ = 4.34 L

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 3.50 L

Initial pressure = 150 Kpa (150/101.325 = 1.5 atm)

Initial temperature = 330 K

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 1.5 atm × 3.50 L × 273 K / 330 K × 1 atm

V₂ = 1433.3 atm .L. K / 330 k.atm

V₂ = 4.34 L

4 0

3 years ago