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pav-90 [236]
2 years ago
15

An actual measurement of a sample is 3.5 m. The measured

Chemistry
2 answers:
zhannawk [14.2K]2 years ago
6 0

Answer:

B. 29 percent

Explanation:

hope this helps

strojnjashka [21]2 years ago
5 0

Answer: b 29 percent

Explanation:

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When doing a titration what is the equivalency point of the neutralization reaction?
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In the compound CO2, how many lone pairs are on the central atom?
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If a 60 kg dog is on a 15 kg sled is pushed with a force of 300 N, what will be dogs acceleration? A) 900 N B) 4 kg C) 4 m/s2 D)
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A jet airplane has a velocity of 1145 knots. A knot is 1 nautical mile (nm)/hr. A nautical
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Answer:

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Explanation:

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4 0
2 years ago
The teacher tells your group to make a stock solution of sodium chloride, and then diluting it to
sergejj [24]

The idea here is that you need to figure out how many moles of magnesium chloride,

MgCl

2

, you need to have in the target solution, then use this value to determine what volume of the stock solution would contain this many moles.

As you know, molarity is defined as the number of moles of solute, which in your case is magnesium chloride, divided by liters of solution.

c

=

n

V

So, how many moles of magnesium chloride must be present in the target solution?

c

=

n

V

⇒

n

=

c

⋅

V

n

=

0.158 M

⋅

250.0

⋅

10

−

3

L

=

0.0395 moles MgCl

2

Now determine what volume of the target solution would contain this many moles of magnesium chloride

c

=

n

V

⇒

V

=

n

c

V

=

0.0395

moles

3.15

moles

L

=

0.01254 L

Rounded to three sig figs and expressed in mililiters, the volume will be

V

=

12.5 mL

So, to prepare your target solution, use a

12.5-mL

sample of the stock solution and add enough water to make the volume of the total solution equal to

250.0 mL

.

This is equivalent to diluting the

12.5-mL

sample of the stock solution by a dilution factor of

20

.

3 0
2 years ago
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