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Dafna11 [192]
3 years ago
8

Calculate [OH−] for each solution.

Chemistry
1 answer:
Triss [41]3 years ago
6 0

Answer:

1.  [OH⁻] = 0.30 M ; 2. [OH⁻] = 1.54x10⁻⁶M ; 3. [OH⁻] = 1.32x10⁻¹³M

Explanation:

Remember the rule:

pH + pOH = 14

pOH = 14 - pH

10*⁻pOH (you have to elevate 10, to -pOH)

10*⁻pOH  = [OH⁻]

1. 14 - 13.48 = 0.52

10⁻⁰°⁵² = 0.30

2. 14 - 8.19 = 5.81

10⁻⁵°⁸¹ = 1.54x10⁻⁶

3. 14 - 2.12 = 12.88

10⁻¹²°⁸⁸ = 1.32x10⁻¹³

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Answer:

C

Explanation:

The answer is C because machines such as tractors and sprinklers are counted as technology, and are better examples than pesticides.

5 0
3 years ago
Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W
nikklg [1K]

Answer:

There are 3 steps of this problem.

Explanation:

Step 1.

Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.

Step 2.

Enthalpy of saturated liquid Haq = 781.124 J/g

Enthalpy of saturated vapour Hvap = 2779.7 J/g

Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g

Step 3.

In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy

So, H1=H2

     H2= (1-x)Haq+XHvap.........1

    Putting the values in 1

    2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}

                        = 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)

1904.976 (J/g) = x1998.576 (J/g)

                     x = 1904.976 (J/g)/1998.576 (J/g)

                     x = 0.953

So, the quality of the wet steam is 0.953

                   

7 0
3 years ago
Read 2 more answers
Adding more than one equivalent of HCl to pent-1-yne will lead to which product:______.
Ket [755]

Answer:

c. 2,2-dichloropentane.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to firstly draw the structure of the reactant, pent-1-yne:

CH\equiv C-CH_2-CH_2-CH_2

Now, we infer the halogen is added to the carbon atom with the most carbon atoms next to it, in this case, carbon #2, in order to write the following product:

CH\equiv C-CH_2-CH_2-CH_2+2HCl\rightarrow CH_3- CCl_2-CH_2-CH_2-CH_2

Whose name is 2,2-dichloropentane.

Regards!

8 0
3 years ago
What is the pH of 0.12M HNO3
Phoenix [80]

Answer:

pH= 0.92

Explanation:

HNO3-> H^+ +NO3^-

HNO3 is a strong acid, so it fully dissociates

[HNO3] = 0.12M    [H^+] = 0.12M  

pH= -log[H^+]

pH=-log[.12] = 0.92

pH = 0.92

4 0
3 years ago
In a balanced chemical equation the mass of the reactants and products are equal.
vova2212 [387]

Answer:

TRUE

Explanation:

3 0
3 years ago
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