All categories

3 years ago

Gummy gummy bears gummy gummy bears

Engineering

2 answers:

ivanzaharov [21]3 years ago

8 0

I love that song lol

Dima020 [189]3 years ago

8 0

Answer:

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh yeaoooh

Gummy Gummy Gummy Gummy Gummibär

Bai ding ba doli party

Bamm bing ba doli party

Breding ba doli party

Party pop

Bai ding ba doli party

Bamm bing ba doli party

Breding ba doli party

Party pop

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh yeaoooh

Ba Ba Bidubidubi Yum Yum

Three times, you can bite me

Ba Ba Bidubidubi Yum Yum

Three times, you can bite me

Gummy Gummy Gummy Gummy Gummibär

Én vagyok a gumimaci

Gyere már gyere velem

Gyere táncolj már kérlek get get party pop

Én vagyok a gumicummi

Cicci meg a kodile a mambó csoda

Pápé gyere már és táncolj party pop

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Party pop

You might be interested in

determine the position d of the 6- kn load so that the average normal stress in each rod is the same.

Zinaida [17]

The load is placed at distance 0.4 L from the end of $$12 \mathrm{~mm}^{2}$ area.

<h3>What is meant by torque?</h3>

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is torque.

Let the beam is of length L

Now the stress on both the end is the same now we can say that torque on the beam due to two forces must be zero

$N_1 * x=N_2 *(L-x)$

also, we know that stress at both ends are same

$\frac{N_1}{12}=\frac{N_2}{8}$

$2 * N_1=3 * N_2$

Now from two equations we have

$$\frac{3}{2} N_2 * x=N_2 *(L-x)$

solving the above equation we have

$$x=\frac{2}{5} L$

so the load is placed at distance 0.4 L from the end of $$12 \mathrm{~mm}^{2}$ area.

The complete question is:

47. the beam is supported by two rods ab and cd that have cross-sectional areas of $$$12mm^2$ and $$$8mm^2$ , respectively. determine the position d of the 6-kn load so that the average normal stress in each rod is the same.

To learn more about torque refer to:

brainly.com/question/20691242

#SPJ4

7 0

2 years ago

Which of the following is NOT associated with Urban Sprawl?

pochemuha

The option that is not associated with the given term called urban sprawl is; Option A: Blocking high views

What is Urban Sprawl?

Urban sprawl is defined as the rapid expansion of the geographic boundaries of towns and cities which is often accompanied by low-density residential housing and increased reliance on the private automobilefor movement.

Looking at the given options, "blocking high views" is the option that is not typically a problem associated with urban sprawl because urbanization usually takes place on relatively flat levels.

The missing options are;

a. blocking high views

b. destroying animal habitats

c. overrunning farmland

d. reducing green space

Read more about urban sprawl at; brainly.com/question/504389

8 0

2 years ago

A heat pump with an ideal compressor operates between 0.2 MPa and 1 MPa. Refrigerant R134a flows through the system at a rate of

solmaris [256]

Answer:

The mass flow rate of refrigerant is 0.352 kg/s

Explanation:

Considering the cycle of an ideal heat pump, provided in the attachment, we first find enthalpy at state B and D. For that purpose, we use property tables of refrigerant R134a:

At State A:

From table, we see the enthalpy and entropy value of saturated vapor at 0.2 MPa. Therefore:

ha = 244.5 KJ/kg

Sa = 0.93788 KJ/kg.k

At State B:

Since, the process from state A to B is isentropic. Therefore,

Sb = Sa = 0.93788 KJ/Kg

From table, we see the enthalpy value of super heated vapor at 1 MPa and Sb. Therefore:

hb = 256.85 KJ/kg (By interpolation)

At State C:

From table, we see the enthalpy and entropy value of saturated liquid at 1 MPa. Therefore:

hc = 107.34 KJ/kg

Now, from the diagram it is very clear that:

Heat Loss = m(hb = hc)

m = (Heat Loss)/(hb - hc)

where,

m = mass flow rate = ?

Heat Loss = (180,000 Btu/hr)(1.05506 KJ/1 Btu)(1 hr/3600 sec)

Heat Loss = 52.753 KW

Therefore,

m = (52.753 KJ/s)/(256.85 KJ/kg - 107.34 KJ/kg)

m = 0.352 kg/s

5 0

3 years ago

Fill in the blank to correctly complete the statement below.

frutty [35]

Answer:

The invention of the pendulum-driven ___clocks___ in the 1600s paved the way for a new industrial era.

4 0

3 years ago

A vertical pole consisting of a circular tube of outer diameter 127 mm and inner diameter 115 mm is loaded by a linearly varying

Anna [14]

Maximum shear stress in the pole is 0.

Explanation:

Given-

Outer diameter = 127 mm

Outer radius, $r_{2}$ = 127/2 = 63.5 mm

Inner diameter = 115 mm

Inner radius, $r_{1}$ = 115/2 = 57.5 mm

Force, q = 0

Maximum shear stress, τmax = ?

τmax $= \frac{4q}{3\pi } (\frac{r2^2 + r2r1 + r1^2}{r2^4 - r1^4} )$

If force, q is 0 then τmax is also equal to 0.

Therefore, maximum shear stress in the pole is 0.

3 0

3 years ago