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3 years ago

Gummy gummy bears gummy gummy bears

Engineering

2 answers:

ivanzaharov [21]3 years ago

8 0

I love that song lol

Dima020 [189]3 years ago

8 0

Answer:

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh yeaoooh

Gummy Gummy Gummy Gummy Gummibär

Bai ding ba doli party

Bamm bing ba doli party

Breding ba doli party

Party pop

Bai ding ba doli party

Bamm bing ba doli party

Breding ba doli party

Party pop

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh yeaoooh

Ba Ba Bidubidubi Yum Yum

Three times, you can bite me

Ba Ba Bidubidubi Yum Yum

Three times, you can bite me

Gummy Gummy Gummy Gummy Gummibär

Én vagyok a gumimaci

Gyere már gyere velem

Gyere táncolj már kérlek get get party pop

Én vagyok a gumicummi

Cicci meg a kodile a mambó csoda

Pápé gyere már és táncolj party pop

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Party pop

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kobusy [5.1K]

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I was about to click it on a question I saw.

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2 years ago

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A 40kg steel casting (Cp=0.5kJkg-1K-1) at a temperature of 4500C is quenched in 150kg of oil (Cp=2.5kJkg-1K-1) at 250C. If there

podryga [215]

Of the oil I hope this help

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3 years ago

In plumbing what is a video snake used for

aleksley [76]

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Explanation:

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3 years ago

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To provide some perspective on the dimensions of atomic defects, consider a metal specimen that has a dislocation density of 105

GenaCL600 [577]

Answer:

$62.14\ \text{miles}$

$6213727.37\ \text{miles}$

Explanation:

The distance of the chain would be the product of the dislocation density and the volume of the metal.

Dislocation density = $10^5\ \text{mm}^{-2}$

Volume of the metal = $1000\ \text{mm}^3$

$10^5\times 1000=10^8\ \text{mm}\\ =10^5\ \text{m}$

$1\ \text{mile}=1609.34\ \text{m}$

$\dfrac{10^5}{1609.34}=62.14\ \text{miles}$

The chain would extend $62.14\ \text{miles}$

Dislocation density = $10^{10}\ \text{mm}^{-2}$

Volume of the metal = $1000\ \text{mm}^3$

$10^{10}\times 1000=10^{13}\ \text{mm}\\ =10^{10}\ \text{m}$

$\dfrac{10^{10}}{1609.34}=6213727.37\ \text{miles}$

The chain would extend $6213727.37\ \text{miles}$

3 0

3 years ago

A heat recovery system (HRS) is used to conserve heat from the surroundings and supply it to the Mars Rover. The HRS fluid loop

blagie [28]

Answer:

0.304 L of Freon is needed

Explanation:

Q = mCT

Q is quantity of energy that must be removed = 47 BTU = 47×1055.06 = 49587.82 J

C is specific heat of Freon = 74 J/mol.K = 74 J/mol.K × 1 mol/120 g = 0.617 J/g.K

T is temperature in the area of Mars = 189 K

m = Q/CT = 49587.82/(0.617×189) = 452.23 g = 452.24/1000 = 0.45223 kg

Density of Freon = specific gravity of Freon × density of water = 1.49 × 1000 kg/m^3 = 1490 kg/m^3

Volume of Freon = mass/density = 0.45223/1490 = 0.000304 m^3 = 0.000304×1000 = 0.304 L

7 0

3 years ago