All categories

3 years ago

Gummy gummy bears gummy gummy bears

Engineering

2 answers:

ivanzaharov [21]3 years ago

8 0

I love that song lol

Dima020 [189]3 years ago

8 0

Answer:

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh yeaoooh

Gummy Gummy Gummy Gummy Gummibär

Bai ding ba doli party

Bamm bing ba doli party

Breding ba doli party

Party pop

Bai ding ba doli party

Bamm bing ba doli party

Breding ba doli party

Party pop

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh yeaoooh

Ba Ba Bidubidubi Yum Yum

Three times, you can bite me

Ba Ba Bidubidubi Yum Yum

Three times, you can bite me

Gummy Gummy Gummy Gummy Gummibär

Én vagyok a gumimaci

Gyere már gyere velem

Gyere táncolj már kérlek get get party pop

Én vagyok a gumicummi

Cicci meg a kodile a mambó csoda

Pápé gyere már és táncolj party pop

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Oh, I'm a gummy bear

Yes, I'm a gummy bear

Oh, I'm a yummy, tummy, funny, lucky gummy bear

I'm a jelly bear

'Cause I'm a gummy bear

Oh, I'm a movin', groovin', jammin', singin' gummy bear

Party pop

You might be interested in

A circular specimen of MgO is loaded in three-point bending. Calculate the minimum possible radius of the specimen without fract

Hitman42 [59]

Answer:

radius = 9.1 × $10^{-3}$ m

Explanation:

given data

applied load = 5560 N

flexural strength = 105 MPa

separation between the support = 45 mm

solution

we apply here minimum radius formula that is

radius = $\sqrt[3]{\frac{FL}{\sigma \pi}}$ .................1

here F is applied load and is length

put here value and we get

radius = $\sqrt[3]{\frac{5560\times 45\times 10^{-3}}{105 \times 10^6 \pi}}$

solve it we get

radius = 9.1 × $10^{-3}$ m

8 0

2 years ago

When engineers design solutions to problems (bridge a river, support a building, etc.) there are always certain conditions which

zheka24 [161]

Explanation:

what is your main question

6 0

2 years ago

Write a simple phonebook program that reads in a series of name-number pairs from the user (that is, name and number on one line

Vlad1618 [11]

Answer:

import java.util.HashMap;

import java.util.Map;

import java.util.Scanner;

public class PhoneBook {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

Map<String, String> map = new HashMap<>();

String name, number, choice;

do {

System.out.print("Enter name: ");

name = in.next();

System.out.print("Enter number: ");

number = in.next();

map.put(name, number);

System.out.print("Do you want to try again(y or n): ");

choice = in.next();

} while (!choice.equalsIgnoreCase("n"));

System.out.print("Enter name to search for: ");

name = in.next();

if (map.containsKey(name)) {

System.out.println(map.get(name));

} else {

System.out.println(name + " is not in the phone book");

}

6 0

2 years ago

*100 POINTS*

jenyasd209 [6]

Answer:

Depending on the size of the shrubs and the tress, will give you a general idea on how long they take to grow. Unless there are small plants that take forever to grow and or large plants that grow quickly. Hope this helps....

Explanation:

3 0

3 years ago

Read 2 more answers

Daniel Wiseman, a scientist for Gres-Trans Corp., wants to determine if the flow rate of a particular material changes with diff

kiruha [24]

Answer: C. There is no relationship

Explanation:

At the various temperatures, the flow rates do not seem to show any relation as similar temperatures can yield different flow rates.

The flow rates neither appear to generally increase nor decrease as a result of a decrease or an increase in temperature which means that there is a lack of a positive, negative and curvilinear relationship.

There is simply no relationship.

4 0

2 years ago