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Brilliant_brown [7]
3 years ago
13

Why should engineers avoid obvious patterns?

Engineering
2 answers:
lozanna [386]3 years ago
5 0

Answer:

Patterns may cloud the vision of the design process and send the engineer off track.

Explanation:

Engineers use a cyclical process and must stay on track during this process. A key point to an engineer is being able to have the ability to use creative and critical thinking.

seraphim [82]3 years ago
5 0

Answer:

Patterns tend to impose a prescribed way of thinking that will limit possible solutions.

Explanation:

While patterns help scientists and mathematicians solve problems, engineers should avoid obvious patterns. These patterns tend to lock in a prescribed way of thinking that will limit possible solutions. While making observations is helpful, don't force them into categories. Watch for observations that are unexpected, and compare and contrast all information before deciding on a final solution.

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The dry unit weight of a soil sample is 14.8 kN/m3.
Jlenok [28]

Answer:

See attachment for completed question

Explanation:

Given that; Brainly.com

What is your question?

mkasblog

College Engineering 5+3 pts

The dry unit weight of a soil sample is 14.8 kN/m3.

Given that G_s = 2.72 and w = 17%, determine:

(a) Void ratio

(b) Moist unit weight

(c) Degree of saturation

(d) Unit weight when the sample is fully saturated

See complete solving at attachment

4 0
3 years ago
The yield of a chemical process is being studied.The two most important variables are thought to be the pressure and the tempera
anyanavicka [17]

Answer:

<u>note:</u>

<u>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</u>

Download docx
7 0
3 years ago
A closed, rigid tank is filled with a gas modeled as an ideal gas, initially at 27°C and gauge pressure of 300 kPa. The gas is h
Sergio [31]

Answer:

the final temperature is 77.1 °C

Explanation:

Given the data in the question;

Initial temperature; T₁ = 27°C = ( 27 + 273)K = 300 K

Initial absolute pressure P₁ = 300 kPa = ( 300 + 101.325 )kPa = 401.325 kPa

Final absolute pressure P₂ = 367 kPa = ( 367 + 101.325 )kPa = 468.325 kPa

Now, to calculate the final temperature, we use the ideal gas equation;

P₁V/T₁ = P₂V/T₂

but it is mentioned that the rigid tank is closed,

so the volume is the same both before and after.

Change in volume = 0

hence;

P₁/T₁ = P₂/T₂

we substitute

401.325 kPa / 300 K = 468.325 kPa / T₂

T₂ × 401.325 kPa  = 300 K × 468.325 kPa

T₂ = [ 300 K × 468.325 kPa ] / 401.325 kPa

T₂ = 140497.5 K / 401.325

T₂ =  350.08 K

T₂ = ( 350.08 - 273 ) °C

T₂ = 77.1 °C

Therefore, the final temperature is 77.1 °C

3 0
3 years ago
Which type of system is being researched to deliver power to several motors to drive multiple systems in vehicles?
qaws [65]

Answer:

pneumatic power system

Explanation:

pneumatic power can be used to quietly operate power windows, door locks, power mirrors, and much much more, also negative pressure pneumatics (vacuum) is used to control many engine and fuel systems

8 0
2 years ago
*6–24. The beam is used to support a dead load of 400 lb&gt;ft, a live load of 2 k&gt;ft, and a concentrated live load of 8 k. D
lisabon 2012 [21]

Answer:

(a) maximum positive reaction at A = 64.0 k

(b) maximum positive shear at A = 32.0 k

(c) maximum negative moment at C = -540 k·ft

Explanation:

Given;

dead load  Gk = 400 lb/ft

live load Qk = 2 k/ft

concentrated live load Pk =8 k

(a) from the influence line for vertical reaction at A, the maximum positive reaction is

A_{ymax} = 2*(8) +(1/2(20 - 0)* (2))*(2 + 0.4) = 64 k

See attachment for the calculations of (b) & (c) including the influence line

3 0
3 years ago
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