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Brilliant_brown [7]
3 years ago
13

Why should engineers avoid obvious patterns?

Engineering
2 answers:
lozanna [386]3 years ago
5 0

Answer:

Patterns may cloud the vision of the design process and send the engineer off track.

Explanation:

Engineers use a cyclical process and must stay on track during this process. A key point to an engineer is being able to have the ability to use creative and critical thinking.

seraphim [82]3 years ago
5 0

Answer:

Patterns tend to impose a prescribed way of thinking that will limit possible solutions.

Explanation:

While patterns help scientists and mathematicians solve problems, engineers should avoid obvious patterns. These patterns tend to lock in a prescribed way of thinking that will limit possible solutions. While making observations is helpful, don't force them into categories. Watch for observations that are unexpected, and compare and contrast all information before deciding on a final solution.

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6, Large, centralized power-generating stations are often located near ___. A) areas without natural energy sources B) abundant
Leviafan [203]

Answer: abundant energy sources

Explanation:

A power generating station which is sometimes referred to as the power plant is simply an industrial facility that is used for the generation of power.

Large, centralized power-generating stations are often located near abundant energy sources. It should be noted that most power stations burn fossil fuels like oil, coal, natural gas, in order to be able to generate power and hence, they have to be located where there's abundance of the energy sources.

8 0
3 years ago
The steady-state data listed below are claimed for a power cycle operating between hot and cold reservoirs at 1200K and 400K, re
Anni [7]

Answer:

a) W_cycle = 200 KW , n_th = 33.33 %  , Irreversible

b) W_cycle = 600 KW , n_th = 100 %     , Impossible

c) W_cycle = 400 KW , n_th = 66.67 %  , Reversible

Explanation:

Given:

- The temperatures for hot and cold reservoirs are as follows:

  TL = 400 K

  TH = 1200 K

Find:

For each case W_cycle , n_th ( Thermal Efficiency ) :

(a) QH = 600 kW, QC = 400 kW

(b) QH = 600 kW, QC = 0 kW

(c) QH = 600 kW, QC = 200kW

- Determine whether the cycle operates reversibly, operates irreversibly, or is impossible.

Solution:

- The work done by the cycle is given by first law of thermodynamics:

                                 W_cycle = QH - QC

- For categorization of cycle is given by second law of thermodynamics which states that:

                                 n_th < n_max     ...... irreversible

                                 n_th = n_max     ...... reversible

                                 n_th > n_max     ...... impossible

- Where n_max is the maximum efficiency that could be achieved by a cycle with Hot and cold reservoirs as follows:

                                n_max = 1 - TL / TH = 1 - 400/1200 = 66.67 %

And,                         n_th = W_cycle / QH

a) QH = 600 kW, QC = 400 kW

   - The work done by cycle according to First Law is:

                                W_cycle = 600 - 400 = 200 KW

   - The thermal efficiency of the cycle is given by n_th:

                                n_th = W_cycle / QH

                                n_th = 200 / 600 = 33.33 %

   - The type of process according to second Law of thermodynamics:

               n_th = 33.333 %                n_max = 66.67 %

                                       n_th < n_max  

      Hence,                Irreversible Process  

b) QH = 600 kW, QC = 0 kW

   - The work done by cycle according to First Law is:

                                W_cycle = 600 - 0 = 600 KW

   - The thermal efficiency of the cycle is given by n_th:

                                n_th = W_cycle / QH

                                n_th = 600 / 600 = 100 %

   - The type of process according to second Law of thermodynamics:

                 n_th = 100 %                 n_max = 66.67 %

                                     n_th > n_max  

      Hence,               Impossible Process              

c) QH = 600 kW, QC = 200 kW

   - The work done by cycle according to First Law is:

                                W_cycle = 600 - 200 = 400 KW

   - The thermal efficiency of the cycle is given by n_th:

                                n_th = W_cycle / QH

                                n_th = 400 / 600 = 66.67 %

   - The type of process according to second Law of thermodynamics:

               n_th = 66.67 %                 n_max = 66.67 %

                                     n_th = n_max  

      Hence,                Reversible Process

7 0
3 years ago
How to find Catenary length in sag
Gnom [1K]

Answer:

buter uwu heheheheh joke

6 0
2 years ago
Your program must output each student’s name in the form: last name followed by a comma, followed by a space, followed by the fi
Reptile [31]

Answer:

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

char getStudentGrade(int testScore);

//Declare constant max students in file 10

const int maxStudents = 10;

struct StudentType

{

  string studentFName;

  string studentLName;

  int testScore;

  char grade;

};

void readStudentData(StudentType students[]){

  int i = 0;

 

  ifstream infile;

  infile.open("inputStudentData.txt");

 

 

  while (!infile.eof())

  {

   infile >> students[i].studentFName;

   infile >> students[i].studentLName;

   infile >> students[i].testScore;

   students[i].grade = getStudentGrade(students[i].testScore);

      i++;

  }

}

char getStudentGrade(int testScore){

  char grade;

  if(testScore >= 80) {

      grade = 'A';      

  }

  else if(testScore >= 60) {

      grade = 'B';

  }

  else if(testScore >= 50) {

      grade = 'C';  

  }

  else if(testScore >= 40) {

      grade = 'D';      

  }

  else {

      grade = 'F';  

  }

  return grade;

}

int main()

{

 

  StudentType students[10];

 

  readStudentData(students);

 

  for(int i=0;i<maxStudents;i++) {

      students[i].grade = getStudentGrade(students[i].testScore);

  }

 

  for(int i=0; i<maxStudents; i++){    

      cout << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

  }

  ofstream outputFile;

  outputFile.open ("outputStudentData.txt");

 

  for(int i=0; i<maxStudents; i++){    

      outputFile << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

  }

  outputFile.close();

  return 0;

}

3 0
4 years ago
During experiments on laser etching of microchips for IBM, a nuclear engineer places a discshaped sample 5 mm in diameter in a v
Andru [333]

Answer:

Steady state temperature is approximately 801K

Explanation:

Detailed explanation and calculation is shown in the images below.

7 0
3 years ago
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