Answer
a) 62 percent
b) 40 percent
Explanation:
Original diameter ( d ) = 10.33 mm
Original Gauge length ( L ) = 52.8 mm
diameter at point of fracture ( d ) = 6.38 mm
New gauge length ( L ) = 73.9 mm
<u>Calculate ductility in terms of</u>
a) percent reduction in area
percentage reduction = [ (A - A ) / A ] * 100
A ( initial area ) = π /4 di^2
= π /4 * ( 10.33 )^2 = 83.81 mm^2
A ( final area ) = π /4 df^2
= π /4 ( 6.38)^2 = 31.97 mm^2
hence : %reduction = ( 83.81 - 31.97 ) / 83.81
= 0.62 = 62 percent
b ) percent elongation
percentage elongation = ( L - L ) / L
= ( 73.9 - 52.8 ) / 52.8 = 0.40 = 40 percent